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3 years ago

How many solutions does the system have? Explain. −3x + 6y = 10 −3x + 6y = −4

Mathematics

1 answer:

Temka [501]3 years ago

8 0

Answer:

none

Step-by-step explanation:

-3x + 6y cannot equal both 10 and -4 because 10 ≠ -4

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Please help!!!!!!!!!!

Basile [38]

Answer:

1-c

2-b

3-a

Step-by-step explanation:

1. 7y=14

y=2

-7y=-14

y=2

so the equation has one solution

2. 0=0

so the equation has infinite solution

3. 0=2 false

so the equation has no solution

6 0

3 years ago

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Luke grew some carrots in his garden. Their weights, in grams, are listed below.

Arisa [49]

Answer:

The bottom right histogram is the correct one.

Step-by-step explanation:

Carrots weight 40-49 kg = 2

... of weight 50-59 = 6

... of weight 60-69 = 4

.. of weight 70-79 = 1

8 0

2 years ago

Some banks now use continuous compounding of an amount invested. In this case, the equation that models the value of an initial

Komok [63]

Answer:

In this case, the equation that models the value of an initial investment of P dollars in t years at an annual interest rate of r is given by A = Pert.

Step-by-step explanation:

4 0

2 years ago

2m = 1 + m what do I need to do to solve this problem

Anvisha [2.4K]

First you have to subtract the m on the right from the left so it would just end up being m = 1

Hope this helps

-Ayden

8 0

3 years ago

Read 2 more answers

Find the exact value of each trigonometric function for the given angle θ.

Kay [80]

Answer:

$\sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=\dfrac{2}{\sqrt{3}}.$

Step-by-step explanation:

The given angle is 240 degrees.

We need to find the exact value of each trigonometric function for the given angle θ.

Since $\theta=240$ , it means θ lies in 3rd quadrant. In 3d quadrant only tan and cot are positive.

$\sin (240^\circ)=\sin (180^\circ+60^\circ)=-\sin (60^\circ)=-\dfrac{\sqrt{3}}{2}$

$\cos (240^\circ)=\cos (180^\circ+60^\circ)=-\cos (60^\circ)=-\dfrac{1}{2}$

$\tan (240^\circ)=\tan (180^\circ+60^\circ)=\tan (60^\circ)=\sqrt{3}$

$\cot (240^\circ)=\cot (180^\circ+60^\circ)=\cot (60^\circ)=\dfrac{1}{\sqrt{3}}$

$\sec (240^\circ)=\sec (180^\circ+60^\circ)=-\sec (60^\circ)=-2$

$\csc (240^\circ)=\csc (180^\circ+60^\circ)=-\csc (60^\circ)=-\dfrac{2}{\sqrt{3}}$

Therefore, $\sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=-\dfrac{2}{\sqrt{3}}.$

8 0

3 years ago