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inn [45]
3 years ago
6

The following diagram shows the path of a planet around the Sun. Kepler discovered that _____.

Mathematics
2 answers:
Phantasy [73]3 years ago
7 0

The right answer is:

<em>area B = area C</em>

We can solve this problem by using Kepler's laws of planetary motion. There are three Kepler's laws. In this exercise, we need to use the second law. According to this law,<em> a line segment joining a planet and the sun sweeps out equals areas during equals intervals of time. </em>So, a certain planet sweeps out an <em>area B </em>from the point <em>P3 </em>to <em>P4</em> in an interval of time <em>t. </em>On the other hand, for the same interval of time <em>t, </em>the planet sweeps out an <em>area C </em>from point <em>P4</em> to <em>P5, </em>that is equal to the previous area according to second kepler's law.

vesna_86 [32]3 years ago
3 0
<span>Kepler giscovered that area B = area C because they have the same time interval..</span>
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5 0
4 years ago
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jek_recluse [69]

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\boxed{ \bold{ \huge{ \boxed{ \sf{13 \: ft}}}}}

Step-by-step explanation:

\star{ \sf{ \: Area \: of \: a \: square \: rug \: ( \: A \: ) \:  =  \: 169 \:  {ft}^{2} }}

\sf{ \underline{Finding \: the \: length \: of \: a \: square \: ( \: l \: )}}

\boxed{ \sf{Area \: of \: a \: square \:  =  \:  {l}^{2} }}

\hookrightarrow{ \sf{169 =  {l}^{2} }}

\hookrightarrow{ \sf{ {l}^{2}  = 169}}

\hookrightarrow{ \sf{ \sqrt{ {(l)}^{2} }  =  \sqrt{169} }}

\hookrightarrow{ \text{length \:  =  \: 13 \: ft}}

\text{Hope \: I \: helped!}

\text{Best \: wishes !!}

~\text{TheAnimeGirl}

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