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saw5 [17]
3 years ago
6

Find the greatest common factor of thefollowing monomials:12b 40b4​

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
8 0

Answer:

4b

Step-by-step explanation:

The GCF is the largest number that will multiply into each term. It can be both numbers and letters.

12b = 2*2*3*b and 40b^4 = 2*2*2*5*b*b*b*b has GCF 2*2*b = 4b

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The cost to rent a car at one agency is $24.50 per day plus an additional $15.99 fee for insurance. At a different agency, the c
Lena [83]

Answer:

d=4

Step-by-step explanation:

Agency 1:

Total cost of renting a car=24.50d + 15.99

Agency 2:

Total cost of renting a car=27.50d + 3.99

Where, d=No. of days of renting the car

Which equation could be used to find the number of days, d, at which the rental fee is the same for both agencies?

The equation is by equating agency 1 and agency 2 equation

24.50d + 15.99 = 27.50d + 3.99

Collect like terms

24.50d - 27.50d = 3.99 - 15.99

-3d = -12

Divide both sides by -3

d= -12 / -3

=4

d=4

Check

Agency 1:

24.50d + 15.99

= 24.50(4) + 15.99

= 98 + 15.99

= 113.99

Agency 2:

27.50d + 3.99

= 27.50(4) + 3.99

= 110 + 3.99

= 133.99

3 0
3 years ago
Where is point b on the number line?​
Yuliya22 [10]

Answer:

i dont know but can you pick me brainiest

Step-by-step explanation:

4 0
3 years ago
Why did you multiply 15 by 3?
navik [9.2K]
To get an answer which is....45
8 0
3 years ago
Read 2 more answers
Which of the following is in order from least to greatest
vovangra [49]
The third option is ordered least to greatest
4 0
3 years ago
Find the points on the ellipse 4x2 + y2 = 4 that are farthest away from the point (−1, 0).
Hitman42 [59]
<span>The two points that are most distant from (-1,0) are exactly (1/3, 4sqrt(2)/3) and (1/3, -4sqrt(2)/3) approximately (0.3333333, 1.885618) and (0.3333333, -1.885618) Rewriting to express Y as a function of X, we get 4x^2 + y^2 = 4 y^2 = 4 - 4x^2 y = +/- sqrt(4 - 4x^2) So that indicates that the range of values for X is -1 to 1. Also the range of values for Y is from -2 to 2. Additionally, the ellipse is centered upon the origin and is symmetrical to both the X and Y axis. So let's just look at the positive Y values and upon finding the maximum distance, simply reflect that point across the X axis. So y = sqrt(4-4x^2) distance is sqrt((x + 1)^2 + sqrt(4-4x^2)^2) =sqrt(x^2 + 2x + 1 + 4 - 4x^2) =sqrt(-3x^2 + 2x + 5) And to simplify things, the maximum distance will also have the maximum squared distance, so square the equation, giving -3x^2 + 2x + 5 Now the maximum will happen where the first derivative is equal to 0, so calculate the first derivative. d = -3x^2 + 2x + 5 d' = -6x + 2 And set d' to 0 and solve for x, so 0 = -6x + 2 -2 = -6x 1/3 = x So the furthest point will be where X = 1/3. Calculate those points using (1) above. y = +/- sqrt(4 - 4x^2) y = +/- sqrt(4 - 4(1/3)^2) y = +/- sqrt(4 - 4(1/9)) y = +/- sqrt(4 - 4/9) y = +/- sqrt(3 5/9) y = +/- sqrt(32)/sqrt(9) y = +/- 4sqrt(2)/3 y is approximately +/- 1.885618</span>
7 0
4 years ago
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