Question

Find mㄥPQR if ray QT bisects ㄥPQR, mㄥRQT = (10x - 13)°, and mㄥPQT = (6x + 1)°.

Answer 1

It is given in the question that ray QT bisects ㄥPQR.

$m \angle RQT = (10x - 13), \ and \ m \angle PQT = (6x + 1)$

And we have to find the measurement of angle PQR.

Since QT bisects angle PQR,  therefore measurement of angle RQT and angle PQT are equal. That is

$10x-13=6x+1 \\ 4x =14 \\ x = 3.5$

Substituting the value of x, we will get

$m \angle RQT=10*3.5-13 = 22 degree$

And measurement of angle PQR is twice of the measurement of angle RQT, that is

$m \angle PQR= 44$