if u like it,u can start following me...
Submission Received
We will review your information and contact you within 24 hours.
Please do not create new Amazon accounts until we verify your billing information. Any new orders that you place may be delayed or cancelled.
Submission Received
We will review your information and contact you within 24 hours.
Please do not create new Amazon accounts until we verify your billing information. Any new orders that you place may be delayed or cancelled.
Submission Received
We will review your information and contact you within 24 hours.
Please do not create new Amazon accounts until we verify your billing information. Any new orders that you place may be delayed or cancelled.
Submission Received
We will review your information and contact you within 24 hours.
Please do not create new Amazon accounts until we verify your billing information. Any new orders that you place may be delayed or cancelled.
When you multiply 100 times 15 you get 1,500.
Have a great day/night
Answer:
V = 432pi cm^3
Step-by-step explanation:
Pi x r^2 x h
Pi x 6^2 x 12 cm = 432 pi cm^3
Using a discrete probability distribution, it is found that:
a) There is a 0.3 = 30% probability that he will mow exactly 2 lawns on a randomly selected day.
b) There is a 0.8 = 80% probability that he will mow at least 1 lawn on a randomly selected day.
c) The expected value is of 1.3 lawns mowed on a randomly selected day.
<h3>What is the discrete probability distribution?</h3>
Researching the problem on the internet, it is found that the distribution for the number of lawns mowed on a randomly selected dayis given by:
Item a:
P(X = 2) = 0.3, hence, there is a 0.3 = 30% probability that he will mow exactly 2 lawns on a randomly selected day.
Item b:

There is a 0.8 = 80% probability that he will mow at least 1 lawn on a randomly selected day.
Item c:
The expected value of a discrete distribution is given by the <u>sum of each value multiplied by it's respective probability</u>, hence:
E(X) = 0(0.2) + 1(0.4) + 2(0.3) + 3(0.1) = 1.3.
The expected value is of 1.3 lawns mowed on a randomly selected day.
More can be learned about discrete probability distributions at brainly.com/question/24855677