<h3>
Answer: -20</h3>
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Work Shown:
Let x be the location of E on the number line.
Since C is the midpoint of E and F, this means we can find C's location by adding E and F together and dividing that sum by 2
midpoint = (endpoint1 + endpoint2)/2
C = (E+F)/2
Plug in E = x, C = -8 and F = 4. Then solve for x
C = (E+F)/2
-8 = (x+4)/2
(x+4)/2 = -8
x+4 = 2(-8) .... multiplying both sides by 2
x+4 = -16
x = -16-4 .... subtract 4 from both sides
x = -20
The location of point E on the number line is -20
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As a check, lets add E and F to get E+F = -20+4 = -16
Then cut this in half to get -16/2 = -8, which is the proper location of point C
This confirms our answer.
Answer:
She had 22 friends at her graduation party.
Step-by-step explanation:
70 chocolates total minus 3 chocolates times the number of friends she had at the party = 4
70-3x=4
Subtract 70 from both sides of the equation
-3x=4-70
Simplify
-3x=-66
Divide both sides of the equation by -3
-3x/-3=-66/-3
Simplify
x=22
The expression in company B represents that is is in arithmetic progression where first term is 42000 and common difference is 1800 . So we have to use the formula of sum of n terms which is
![S=\frac{n}{2}(2a +(n-1)d)](https://tex.z-dn.net/?f=%20S%3D%5Cfrac%7Bn%7D%7B2%7D%282a%20%2B%28n-1%29d%29%20%20)
Where a is the first term, n is the nth term, d is the common difference
On substituting there values,we will get
![S =\frac{30}{2}(2*42000+(30-1)1800)](https://tex.z-dn.net/?f=%20S%20%3D%5Cfrac%7B30%7D%7B2%7D%282%2A42000%2B%2830-1%291800%29%20%20)
= 15(84000+52200) = 15*136200 =2043000
And for company A, it is
![S= \frac{30}{2}(2*45000+(30-1)1500 ) = 15(90000+43500)=2002500](https://tex.z-dn.net/?f=%20S%3D%20%5Cfrac%7B30%7D%7B2%7D%282%2A45000%2B%2830-1%291500%20%29%20%3D%2015%2890000%2B43500%29%3D2002500%20%20)
Difference between them =2043000-2002500= 40500
So the correct option is the second option .
The answer is 15/18
because if you just put 15/18 it will give you <span>0.83333333333
and for 2/3 it will give you </span><span>0.66666666666
and we all know which number is bigger.
Hope this helps</span>