Step-by-step explanation:
Imagine a line segment on a coordinate plane that rotates around the origin like a clock hand. If it travels 45° (or any positive degree angle), it will travel in a counterclockwise direction. If it rotates -45° degrees (or any negative degree angle), it will travel in a clockwise direction.
Answer:
Kindly check explanation
Step-by-step explanation:
The following mistakes could be explained observed from the plotted bar chart presented in the attachment :
1.) The numeric label of the y-axis which shows the number of text messages isn't well scaled, the numbering did not start from 0, hence this is a defect in the scaling of the bar chart.
2.) Looking closely, the plotted bars do not ALIGN well in terms of spacing as the interval between each bar isn't consistent.
3.) Both the x and y axis of the graph are t labeled thus failing to add a good and meaningful description to the plot especially for first time viewers.
Answer:
Slope=−
2.000
6.000
=−3.000
x−intercept=
3
14
=4.66667
y−intercept=
1
14
=14.00000
Step-by-step explanation:
Please mark brainliest:)
Answer:
y=125a+1
Step-by-step explanation:
Answer:
Roots are not real
Step-by-step explanation:
To prove : The roots of x^2 +(1-k)x+k-3=0x
2
+(1−k)x+k−3=0 are real for all real values of k ?
Solution :
The roots are real when discriminant is greater than equal to zero.
i.e. b^2-4ac\geq 0b
2
−4ac≥0
The quadratic equation x^2 +(1-k)x+k-3=0x
2
+(1−k)x+k−3=0
Here, a=1, b=1-k and c=k-3
Substitute the values,
We find the discriminant,
D=(1-k)^2-4(1)(k-3)D=(1−k)
2
−4(1)(k−3)
D=1+k^2-2k-4k+12D=1+k
2
−2k−4k+12
D=k^2-6k+13D=k
2
−6k+13
D=(k-(3+2i))(k+(3+2i))D=(k−(3+2i))(k+(3+2i))
For roots to be real, D ≥ 0
But the roots are imaginary therefore the roots of the given equation are not real for any value of k.
