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sasho [114]
3 years ago
11

M^6=3/y and M^5=y^2/6 then which of the following expresses m in terms if y

Mathematics
1 answer:
Galina-37 [17]3 years ago
6 0
If y what? I think you're missing part of the question...
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Solve for h .<br><br> -98 = -7 h<br><br> h =
Fofino [41]

Answer:

14

Step-by-step explanation:

Step 1:

- 98 = - 7h       Equation

Step 2:

- 98 ÷ - 7 = h      Divide on both sides

Answer:

h = 14

Hope This Helps :)

8 0
3 years ago
Read 2 more answers
The table shows the amount of money that Bradford saved in his savings account after different amounts of time.
DochEvi [55]
Nice of you to offer 50 points

the constant of proportinality is the sloep or
\frac{change(y)}{change(x)}
x is independent variable and y is dependent variable

the independent variable influences the value of the dependent variable

in this case, the number of months influences the amount of money saved

to find the slope, you do
x=number of months
y=amount

we have
4months, $50
8 months, $100
18 months, $225

or
(x,y)
(4,50)
(8,100)
(18,225)

we can compare

the slope between the points (a,b) and (c,d) is
(d-b)/(c-a)
we can take the slope between any 2 points (assuming the slope is the same, which it is)

(4,50) and (8,100)
slope=(100-50)/(8-4)=50/4=25/2=12.5

the slope is 12.5

2nd option is the answer
3 0
3 years ago
Read 2 more answers
Rewrite 9cos 4x in terms of cos x.
rosijanka [135]
\bf \qquad \textit{Quad identities}\\\\&#10;sin(4\theta )=&#10;\begin{cases}&#10;8sin(\theta )cos^3(\theta )-4sin(\theta )cos(\theta )\\&#10;4sin(\theta )cos(\theta )-8sin^3(\theta )cos(\theta )&#10;\end{cases}&#10;\\\\\\&#10;cos(4\theta)=8cos^4(\theta )-8cos^2(\theta )+1\\\\&#10;-------------------------------\\\\&#10;9cos(4x)\implies 9[8cos^4(x)-8cos^2(x)+1]&#10;\\\\\\&#10;72cos^4(x)-72cos^2(x)+9


---------------------------------------------------------------------------

as far as the previous one on the 2tan(3x)

\bf tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\qquad tan({{ \alpha}} + {{ \beta}}) = \cfrac{tan({{ \alpha}})+ tan({{ \beta}})}{1- tan({{ \alpha}})tan({{ \beta}})}\\\\&#10;-------------------------------\\\\

\bf 2tan(3x)\implies 2tan(2x+x)\implies 2\left[  \cfrac{tan(2x)+tan(x)}{1-tan(2x)tan(x)}\right]&#10;\\\\\\&#10;2\left[  \cfrac{\frac{2tan(x)}{1-tan^2(x)}+tan(x)}{1-\frac{2tan(x)}{1-tan^2(x)}tan(x)}\right]\implies 2\left[ \cfrac{\frac{2tan(x)+tan(x)-tan^3(x)}{1-tan^2(x)}}{\frac{1-tan(x)-2tan^3(x)}{1-tan^2(x)}} \right]&#10;\\\\\\

\bf 2\left[ \cfrac{2tan(x)+tan(x)-tan^3(x)}{1-tan^2(x)}\cdot \cfrac{1-tan^2(x)}{1-tan(x)-2tan^3(x)} \right]&#10;\\\\\\&#10;2\left[ \cfrac{3tan(x)-tan^3(x)}{1-tan^2(x)-2tan^3(x)} \right]\implies \cfrac{6tan(x)-2tan^3(x)}{1-tan^2(x)-2tan^3(x)}
4 0
3 years ago
Two numbers, x and y, are related as described in this statement: x to the power of 3 is equal to y to the power of 5. Which equ
Aleonysh [2.5K]

The mathematical sentence can be written as:

x^3 = y^5

<h3>How to write the expression?</h3>

A number a to the power of n is written as:

a^n

Then:

"x to the power of 3 is equal to y to the power of 5"

Would be written as:

x^3 = y^5

Particularly, this does not appear in the given options, but this is the correct and simplest way of writing the given mathematical sentence.

If you want to learn more about expressions, you can read:

brainly.com/question/4344214

4 0
2 years ago
What's the answer to -7=c-6
son4ous [18]
Simple...

you have: -7=c-6

You want to isolate the variable c

-7=c-6
   
-7=c-6
+6   +6

-1=c

Thus, your answer.
6 0
3 years ago
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