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sasho [114]
2 years ago
11

M^6=3/y and M^5=y^2/6 then which of the following expresses m in terms if y

Mathematics
1 answer:
Galina-37 [17]2 years ago
6 0
If y what? I think you're missing part of the question...
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WhIich of the following mathematical expressions is equivalent to the verbal expression "A number, x, squared is 39 more than th
MrRa [10]

Answer:

E. x^2 = 39 + 10x

Step-by-step explanation:

It helps to do one piece of the sentence at a time.

"A number, x, squared is 39 more than the product of 10 and x"

x

"A number, x, squared is 39 more than the product of 10 and x"

x^2 =

"A number, x, squared is 39 more than the product of 10 and x"

x^2 = 39 +

"A number, x, squared is 39 more than the product of 10 and x"

x^2 = 39 + 10x

Answer: E. x^2 = 39 + 10x

6 0
2 years ago
Read 2 more answers
4x+2=5x-6. I need this solved with all work shown. thank you.​
PtichkaEL [24]

Answer:

Step-by-step explanation:

4x+2=5x-6

4x-5x=-6-2

-x=-8

therefore, x=8

6 0
3 years ago
Read 2 more answers
Select the correct answer.
zhannawk [14.2K]
You have a good day and good luck on that question
8 0
2 years ago
Dee Dee bought an Apple for $0. 85, a sandwich for $4. 50, and a bottle of water for $1. 50. How much did Dee Dee spend?
OLga [1]

To figure out how much she spent all we have to do is add up $0.85, $4.50 and $1.50

$0.85 + $4.50 + $1.50 = $6.85

Therefore she spent $6.85

Hope this helps

8 0
2 years ago
Read 2 more answers
Thetime(inhours)requiredtorepairamachineis an exponentially distributed random variable with parameter λ = 1 . What is 2 (a) the
mihalych1998 [28]

Answer:

a) 0.1353

b) 0.3679

Step-by-step explanation:

Let's start by defining the random variable T.

T : ''The time (in hours) required to repair a machine''

T ~ exp (λ)

T ~ exp (1)

The probability density function for the exponential distribution is

(In the equation I replaced λ = L)

f(x)=Le^{-Lx}

With L > 0 and x ≥ 0

In this exercise λ = 1 ⇒

f(x)=e^{-x}

For a)

P(T>2)

P(T>2)=1-P(T\leq 2)

P(T>2)=1-\int\limits^2_0 {e^{-x} } \, dx

P(T>2)=1-(-e^{-2}+1)

P(T>2)=e^{-2}=0.1353

For b)

P(T\geq 10/T>9)

The event (T ≥ 10 / T > 9) is equivalent to the event T ≥ 1 so they have the same probability of occur

P(T\geq 10/T>9)=P(T\geq 1)

P(T\geq 1)=1-P(T

P(T\geq 1)=1-(-e^{-1}+1)=e^{-1}=0.3679

4 0
2 years ago
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