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2 years ago

Brainliest for right answe

Mathematics

2 answers:

Annette [7]2 years ago

6 0

Umm what do u need help with there is no link attached?

Bingel [31]2 years ago

5 0

Answer:

Hello. add an image!

Step-by-step explanation:

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6th grade math help me pleaseeee

Gnoma [55]

Answer:

1.4

Step-by-step explanation:

9.5+0.9t

=9.5+0.9(-9)

=9.5+-8.1

=1.4

3 0

2 years ago

Read 2 more answers

Eight less than three times a number is -23

Alenkasestr [34]

Answer: 10 is your answer bud ❤

4 0

3 years ago

. CDEF is a trapezium

guajiro [1.7K]

9514 1404 393

Answer:

24 cm²

Step-by-step explanation:

To find the area of the trapezium, we must know the length CD. That means we must know the length BC. Fortunately, the perimeter of ABCF is given, so we have ...

P = 2(AB +BC)

BC = (P/2) -AB = (20 cm)/2 - 6 cm = 4 cm

Then CD is ...

CD = BD -BC = 9 cm -4 cm = 5 cm

The area of the trapezium is given by the formula ...

A = (1/2)(b1 +b2)h

A = (1/2)(5 cm + 3 cm)(6 cm) = 24 cm²

The area of trapezium CDEF is 24 cm².

3 0

2 years ago

I need help asap again pls help me io needd help plzzzzzzzzzzzzzz

Georgia [21]

Answer: isosceles

equilateral is all sides are the same

scalene is all sides dif

isosceles is at least two sides the same

3 0

2 years ago

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Suppose the weights of the Boxers at this club are Normally distributed with a mean of 166 pounds and a standard deviation of 5.

lesya [120]

Answer:

0.1994 is the required probability.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 166 pounds

Standard Deviation, σ = 5.3 pounds

Sample size, n = 20

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling =

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{5.3}{\sqrt{20}} = 1.1851$

P(sample of 20 boxers is more than 167 pounds)

$P( x > 167) = P( z > \displaystyle\frac{167 - 166}{1.1851}) = P(z > 0.8438)$

$= 1 - P(z \leq 0.8438)$

Calculation the value from standard normal z table, we have,

$P(x > 167) = 1 - 0.8006= 0.1994 = 19.94\%$

0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds

3 0

2 years ago