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Karolina [17]
3 years ago
15

Y^2+2y-24 i need help plz

Biology
2 answers:
fredd [130]3 years ago
7 0

y= 6, -4

y 2 − 2 y − 24 = 0

erma4kov [3.2K]3 years ago
4 0

Answer:

[-6,4]

Explanation:

factor

(y+6)(y-4)=0

set each equal to 0

y+6=0  

y=-6

y-4=0

y=4

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1. The container of a breakfast cereal usually lists the number of calories and the amounts of protein, carbohydrate, and fat co
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Complete Question:

The container of a breakfast cereal usually lists the number of calories and the amounts of protein, carbohydrate, and fat contained in one serving of the cereal. The amounts for two common cereals are given below. Suppose a mixture of these two cereals is to be prepared that contains exactly 295 calories, 9 g of protein, 48 g of carbohydrate, and 8 g of fat. a. Set up a vector equation for this problem. Include a statement of what the variables in your equation represent. b. Write an equivalent matrix equation, and then determine if the desired mixture of the two cereals can be prepared.

Nutrient         General mills cheerios        Quaker 100% Natural cereal

Calories                       110                                           130

Protein (g)                    4                                                3

Carbohydrate (g)         20                                             18

Fat (g)                           2                                                 5

Solution:

Representation of data in equation.

x1 is the number of servings of Cheerios and

x2 is the number of servings of Natural Cereal

110x_{1} + 130x_{2}  = 295

4x_{1} + 3x_{2} = 9

20x_{1} + 18x_{2} = 48

2x_{1} + 5x_{2} = 8

Representation of data in vector equation,

x_{1}\left[\begin{array}{ccc}110\\4\\20\\2\end{array}\right]   + x_{2} \left[\begin{array}{ccc}130\\3\\18\\5\end{array}\right]  = \left[\begin{array}{ccc}295\\9\\48\\8\end{array}\right]

Equivalent matrix equation of data

\left[\begin{array}{ccc}110&130&295\\4&3&9\\20&18&48\\2&5&8\end{array}\right]

Row reduce the matrix

\left[\begin{array}{ccc}110&130&295\\4&3&9\\20&18&48\\2&5&8\end{array}\right]  ≅ \left[\begin{array}{ccc}1&0&1.5\\0&1&1\\0&0&0\\0&0&0\end{array}\right]

1.5 serving of cherrios with 1 serving of natural cereal requried to make desired mixture.

x_{1} = 1.5 , x_{2} = 1

a) x_{1} \left[\begin{array}{ccc}110\\4\\20\\2\end{array}\right] + x_{2} \left[\begin{array}{ccc}130\\3\\18\\5\end{array}\right]  =  \left[\begin{array}{ccc}295\\9\\48\\8\end{array}\right]

b) x_{1} = 1.5 , x_{2} = 1

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Answer:

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Explanation:

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Thus, the correct answer is option (d).

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Answer:

Since there is no distinction in the measure of the RNA polymerases yet rather their movement, the distinction lies in their structure and not their grouping. Adjustments are made to widen the states of endurance. Thus E. coli would not constrain it's endurance by restricting its development to hotter temperatures. Thus the appropriate response is "the RNA polymerase sub-units of the P. syringe strain most likely have additional adaptability with the goal that they can move all the more openly in colder temperatures".

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