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Yuri [45]
4 years ago
9

Does anyone know this page for drivers ed?

Computers and Technology
1 answer:
Yuki888 [10]4 years ago
5 0

1. Correct

2. Brake

3. Traffic

4. Pedestrians

5. Crosswalk

6. Left

7. Front

8. Center

9.Nearest

10.Accelerate

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Dani needs to present a mathematical formula to his audience. How should he start the process of adding an equation to a slide?
bonufazy [111]

The principles of creating equations are the same in PowerPoint 2007 and later. Assuming Danny is using PowerPoint 2010, he will click on the insert tab then go ahead and choose the Equation in the symbols group. 

Dani will be able to click on the equation option and use the Equation Tools Design tab or click on the drop down arrow to view more equations






3 0
3 years ago
Brainliest forrrrrrr frrrrrew right herrreeee
nikdorinn [45]

Answer:

Hi!

Explanation:

Thank You So Much For The Points.

5 0
3 years ago
Write a function with two parameters, prefix (a string, using the string class from ) and levels (an unsigned integer). The func
Allisa [31]

Answer:

Here is the program:

#include <iostream>  //to use input output functions

#include <string>  // to use functions to manipulate strings

using namespace std;  //to identify objects cin cout

void function(string prefix, unsigned int levels){  // function that takes two parameters, a string, using the string class and levels an unsigned integer

   if (levels == 0) {  //if number of levels is equal to 0

       cout << prefix << endl;  //displays the value of prefix

       return;    }  

  for (int i = 1; i <=9 ; i++){  //iterates 1 through 9 times

       string sections = (levels == 1 ? "" : ".");  //if the number of levels is equal to 1 then empty space in sections variable otherwise stores a dot

       string output = prefix +  std::to_string(i) + sections;   // displays the string prefix followed by the section numbers. Here to_string is used to convert integer to string

       function(output, levels - 1);   } }   //calls function by passing the resultant string and levels-1  recursively to print the string prefix followed by section numbers

int main() {  // start of main function

   int level = 2;  //determines the number of levels

   function("BOX", level);  } //calls function by passing the string prefix and level value

Explanation:

The program has a function named function() that takes two parameters, prefix (a string, using the string class from ) and levels (an unsigned integer). The function prints the string prefix followed by "section numbers" of the form 1.1., 1.2., 1.3., and so on. The levels argument determines how many levels the section numbers have. If the value of levels is 0 means there is 0 level then the value of prefix is printed. The for loop iterates '1' through '9' times for number of digits in each level. If the number of levels is 1 then space is printed otherwise a dot is printed. The function() calls itself recursively to print the prefix string followed by section numbers.

Let us suppose that prefix = "BOX" and level = 1

If level = 1 then the loop for (int i = 1; i <=9 ; i++) works as follows:

At first iteration:

i = 1

i <=9 is true because value of i is 1

string sections = (levels == 1 ? "" : "."); this statement checks if the levels is equal to 1. It is true so empty space is stored in sections variable so,

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement has prefix i.e BOX plus value of i which is 1 and this int value is converted to string by to_string() method plus sections has an empty space. So this statement becomes

string output = BOX + 1  

So this concatenates BOX with 1 hence output becomes:

output = BOX1

At second iteration:

i = 2

i <=9 is true because value of i is 2

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement becomes

string output = BOX + 2  

So this concatenates BOX with 1 hence output becomes:

output = BOX2

At third iteration:

i = 3

i <=9 is true because value of i is 3

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement becomes

string output = BOX + 3  

So this concatenates BOX with 1 hence output becomes:

output = BOX3

Now at each iteration the prefix string BOX is concatenated and printed along with the value of i. So at last iteration:

At last iteration:

i = 9

i ==9 is true because value of i is 9

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement becomes

string output = BOX + 9  

So this concatenates BOX with 1 hence output becomes:

output = BOX9

After this the loop breaks at i = 10 because the condition i<=9 becomes false. So the output of the entire program is:

BOX1                                                                                                                                          BOX2                                                                                                                                          BOX3                                                                                                                                          BOX4                                                                                                                                          BOX5                                                                                                                                          BOX6                                                                                                                                          BOX7                                                                                                                                          BOX8                                                                                                                                          BOX9  

The program along with the output is attached.

4 0
3 years ago
Which type of unshielded twisted pair (UTP) is commonly used in Ethernet 10BASE-T networks, which carry data at a rate of 10 Mbp
tino4ka555 [31]

Answer:

Category 3 (CAT3) Unshielded Twisted Pair cable

Explanation:

A Category 3 (CAT3) Unshielded Twisted Pair cable is a cable that makes use of the conductivity of copper to transmit data and power. These cables are an older standard for Ethernet cables and can handle data speeds of up to 10mbps.The succeeding standard for Ethernet cables include CAT5 which has speeds of up to 100 mbps, CAT 3 is mostly used in applications where speed is not of great importance such as in PBXs and VoIP telephone systems.

6 0
3 years ago
Which command would you use on a switch to enable management from a remote network?
Savatey [412]
<span>IP default-gateway 192.168.10.185</span>
7 0
4 years ago
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