Answer:
def leap_year(y):
if y % 4 == 0:
return 1
else:
return 0
def number_of_days(m,y):
if m == 2:
return 28 + leap_year(y)
elif m == 1 or m == 3 or m == 5 or m == 7 or m == 8 or m ==10 or m == 12:
return 31
elif m == 4 or m == 6 or m == 9 or m == 11:
return 30
def days(m,d):
if m == 1:
return 0 + d
if m == 2:
return 31 + d
if m == 3:
return 59 + d
if m == 4:
return 90 + d
if m == 5:
return 120 + d
if m == 6:
return 151 + d
if m == 7:
return 181 + d
if m == 8:
return 212 + d
if m == 9:
return 243 + d
if m == 10:
return 273 + d
if m == 11:
return 304 + d
if m == 12:
return 334 + d
def days_left(d,m,y):
if days(m,d) <= 60:
return 365 - days(m,d) + leap_year(y)
else:
return 365 - days(m,d)
print("Please enter a date")
day=int(input("Day: "))
month=int(input("Month: "))
year=int(input("Year: "))
choice=int(input("Menu:\n1) Calculate the number of days in the given month.\n2) Calculate the number of days left in the given year.\n"))
if choice == 1:
print(number_of_days(month, year))
if choice == 2:
print(days_left(day,month,year))
Explanation:
Hoped this helped
import java.util.Scanner;
public class JavaApplication42 {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
int count = 0;
System.out.println("Enter an integer between 0 and 100");
int num = scan.nextInt();
if (num <= 0 || num >= 100){
System.out.println("error");
}
else{
while(num <= 100){
if (count == 20){
System.out.println("");
count = 0;
}
else{
System.out.print(num+" ");
count++;
num++;
}
}
}
}
}
I hope this helps!
Answer:
my hero academia fan!!!!!!
Answer:
The correct answer is: newspaper editor.
Explanation:
Newspaper editors are responsible for creating and updating newspaper material, as well as other outlets such as magazines and, thanks to technology, online papers and newsletters. Such experts must have outstanding grammar and be informative as they are the last knowledge filter before they are sent to the public.
