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bixtya [17]
3 years ago
12

PLEASE HELP ASAP!!!!

Mathematics
1 answer:
OleMash [197]3 years ago
7 0

Answer:

y = -2x + 8

Step-by-step explanation:

The point slope form of an equation is written as

y = mx + c              ...............(i)

Where m is the slope and c is the constant

Now we Know that the equation is

y + 2 = -2(x-5)

and the given points are

m= -2

x = 5

and y= -2

Putting these values in equation (i) to find the value of c

y = mx + c

it becomes

-2 = -2(5) + c

-2 = -10 + c

Adding 10 on both sides

-2 + 10 = -10 + 10 + c

8 = c

or c=8

Now we have the values of m and c

where m= -2 and c = 8

Point slope form of an equation is

y = mx + c

putting the values of m and c to get equation in slope intercept form is

y = (-2)x + 8

or

y = -2x + 8


Other method:

The given point slope form is

y + 2 = -2(x-5)

We have to change it in y= mx + c      form

so solving it

y + 2 = -2x + 10

Subtracting 2 from both sides

y + 2 -2 = -2x + 10 -2

y = -2x + 8

which is same is

y=mx + c

so the required equation is

y = -2x + 8  

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x=\frac{-3+\sqrt{29}}{4},\:x=-\frac{3+\sqrt{29}}{4}\\

Step-by-step explanation:

\left(4x^2+7x-1\right)=\left(4+x\right)\\\mathrm{Refine}\\4x^2+7x-1=4+x\\\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}\\4x^2+7x-1-x=4+x-x\\Simplify\\4x^2+6x-1=4\\\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}\\4x^2+6x-1-4=4-4\\\mathrm{Simplify}\\4x^2+6x-5=0\\\mathrm{For\:}\quad a=4,\:b=6,\:c=-5:\\\quad x_{1,\:2}=\frac{-6\pm \sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}

\frac{-6+\sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}\\=\frac{-6+\sqrt{6^2+4\times \:4\times \:5}}{2\times \:4}\\=\frac{-6+\sqrt{116}}{2\times \:4}\\=\frac{-6+\sqrt{116}}{8}\\\\Let\: simplify\: ; -6+2\sqrt{29}\\=-2\times \:3+2\sqrt{29}\\=2\left(-3+\sqrt{29}\right)\\=\frac{2\left(-3+\sqrt{29}\right)}{8}\\=\frac{-3+\sqrt{29}}{4}\\

\frac{-6-\sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}\\\\=\frac{-6-\sqrt{6^2+4\times \:4\times \:5}}{2\times \:4}\\\\=\frac{-6-\sqrt{116}}{2\times \:4}\\\\=\frac{-6-2\sqrt{29}}{8}\\\\=-\frac{2\left(3+\sqrt{29}\right)}{8}\\\\=-\frac{3+\sqrt{29}}{4}\\\\\\x=\frac{-3+\sqrt{29}}{4},\:x=-\frac{3+\sqrt{29}}{4}

6 0
3 years ago
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Step-by-step explanation:

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6 0
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