Answer:
void mn(int m, int n){
int sum = 0;
int count = 0;
if(m<n){
for(int i = m;i<=n;i++){
sum+=i;
}
}
else{
for(int i = n;i<=m;i++){
sum+=i;
}
}
count = abs(m - n)+1;
cout<<"Sum: "<<sum<<endl;
cout<<"Average: "<<(float)sum/count;
}
Explanation:
This line defines the method
void mn(int m, int n){
This initializes sum and count to 0
int sum = 0;
int count = 0;
This checks if m is less than n
if(m<n){
This iterates from m to n and calculates the sum of numbers between this interval
<em> for(int i = m;i<=n;i++){</em>
<em> sum+=i;</em>
<em> }</em>
<em> }</em>
If otherwise,
else{
This iterates from n to m and calculates the sum of numbers between this interval
<em> for(int i = n;i<=m;i++){</em>
<em> sum+=i;</em>
<em> }</em>
<em> }</em>
This calculates the range from m to n using absolute function
count = abs(m - n)+1;
This prints the calculated sum
cout<<"Sum: "<<sum<<endl;
This calculates and prints the average
cout<<"Average: "<<(float)sum/count;
}
<em>See attachment for complete program that includes the main (in c++)</em>
Answer:
Please find the attachment files of the queries:
Explanation:
In the all queries the select statement is used that selects the defined columns and use the function like sum, join, orderby, and groupby to perform the various operations, in which the sum is used to add columns or rows values, join is used for joining two or more tables, and orderby is used for return the table into ascending or descending order, and groupby is used for the count the value, calculate average and perform other operation and gives its return value.
Answer:
D, if the debtor fails the means test
Explanation:
i took the test on platos and got it right
Answer:
If it is just one letter, use a character, but if it is more than one letter, use a string (string of characters)
It is actually podcast! i took the quiz as well :)
