Answer:
16650 km
Step-by-step explanation:
If plane A leaves from Calgary airport at a nearing of 70 degree, it would end up on the first quadrant. Since we are not given exact bearing here we would assume both planes begin from the first quadrant, they move from North. Example plane A moves North 70 degrees.
Plane B will move North 280 degrees and end up in the fourth quadrant (because each quadrant is 90 degrees so we would have 90+90+90+10=280)
Distance apart = 70+80=150 degrees( since all four quadrants =360 degrees)
1 degree= 111km (approximate metric equivalent of degrees)
Therefore distance apart = 150 degrees ×111km = 16650km
Answer:
4 times
Step-by-step explanation:
This is calculated by putting them in a ratio
Russ's car : Mike's car
9.8 miles per gallon : 39.2 miles per gallon
Converting to fraction
= 9.8/39.2
= 1/4
Hence, we have the ratio:
1 : 4
Hence, Mike's car averages Russ's car 4 times more in miles per gallon
Answer:
a) 6x
b) 2 - y
c) z^4
Step-by-step explanation:
0.90 Is the answer hello hi ahsiodend
Answer:
Lesser x: -9.41
Greater x: -6.59
Step-by-step explanation: khan academy