We have been given that Sebastian got estimates from 7 companies for his kitchen remodel: $ 27,500 ; $31,000 ; $36,000 ; $92,000; $29,000 ; $30,500 ; $28,500. We are asked to find the best measure of center for the given data.
We can see that our given data set has a large valued data point that is $92,000.
We know that mean is very much affected by large valued outliers. The data point $92,000 will increase the mean. Therefore, mean is not a best measure of center for given data.
We know that median is very less affected by outliers, therefore, median will be best measure of center for the given data.
Answer:80m^2
Step-by-step explanation:
Formula for trapezoid
1/2h(b1+b2)
1/2(8)(6+14)
4(20)=80
Answer: the answer is (c)
Step-by-step explanation:
Answer:
285
Step-by-step explanation:
hi
personally this is how i would do this question but there are other ways.
i would start off by seeing how many sundays there are in the month (which is 5) then the number of other days which is 25. i'd then multiply 5 by 510 which is 2550. add that to 240 times 25 (which is 6000) and all of that together is 8550. divide that by the number of the days in the month (30) and then you'll get the daily avergae for the month
hope this helped:)
