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lubasha [3.4K]
3 years ago
10

For every 4 miles Vanessa jogged, Cody jogged 3 miles. If Vanessa jogged 1 mile, how many miles did Cody jog?

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
7 0
Cody has jogged .75 of a mile<span />
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Mason says that (12x + 4) - (-3x + 5) and 15x - 1 are equivalent. Is he correct? Explain
julia-pushkina [17]

Answer:

Yes

Step-by-step explanation:

12x minus -3x is the same as adding two positives. That gives us 15x. 4 - 5 is -1. Putting the two simplified parts of the expression together, we get 15x - 1. Mason is correct.

6 0
3 years ago
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There is a group of student,1/3 are in elementary ,1/2 are in middle school and 15 are in high school. How many are in the group
OverLord2011 [107]
1/2 + 1/3 = 3/6 + 2/6 = 5/6
we have 5/6 so 15 is 1/6 of the entire group
15 × 6 = 90
7 0
3 years ago
Jenee has a package of 30 cards. There are 5 orange cards
padilas [110]

Answer:

1/2 is the best prediction for the number of orange cards that Jenee could get

Step-by-step explanation:

Hope this helps :D

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3 0
3 years ago
Which number is one hundred thousand times larger than 5.6 x 102 ? A) 5.6 x 106 B) 5.6 x 107 C) 5.6 x 108 D) 5.6 x 109
Vladimir [108]
Hello! I believe you are referencing to powers of 10. In this case 10^2 is 100. 5.6 * 100 = 560. Okay. We are looking for the expression that will give the solution that is 100,000 times greater than 560. Okay. 100,000 * 560 is 56,000,000. That is 56 million. In this case, 10^7 is equivalent to 10,000,000, because there are 7 zeros behind the 1. 5.6 * 10^7 is 56,000,000. There. 56 million is 100,000x greater than 560. The answer is B.
8 0
3 years ago
Suppose that in a senior college class of 500500 ​students, it is found that 179179 ​smoke, 228228 drink alcoholic​ beverages, 1
olga2289 [7]

Answer: a) 0.16, b) 0.058, and c) 0.856.

Step-by-step explanation:

Since we have given that

Number of students = 500

Number of students smoke = 179

Number of students drink alcohol = 228

Number of students eat between meals = 119

Number of students eat between meals and drink alcohol = 59

Number of students eat between meals and smoke = 72

Number of students engage in all three = 30

a) Probability that the student smokes but does not drink alcohol is given by

P(S-A)=P(S)-P(S\cap A)\\\\P(S-A)=\dfrac{179}{500}-\dfrac{99}{500}\\\\P(S-A)=\dfrac{179-99}{500}\\\\P(S-A)=\dfrac{80}{500}\\\\P(S-A)=0.16

b) eats between meals and drink alcohol but does not smoke.

P((M\cap A)-S)=P(M\cap A)-P(M\cap S\cap A)\\\\P((M\cap A)-S)=\dfrac{59}{500}-\dfrac{30}{500}\\\\P((M\cap A)-S)=\dfrac{59-30}{500}\\\\P((M\cap A)-S)=\dfrac{29}{500}\\\\P((M\cap A)-S)=0.058

c) neither smokes nor eats between meals.

P(S'\cap M')=1-P(S\cup M)\\\\P(S'\cap M')=1-\dfrac{72}{500}\\\\P(S'\cap M')=\dfrac{500-72}{500}\\\\P(S'\cap M')=\dfrac{428}{500}=0.856

Hence, a) 0.16, b) 0.058, and c) 0.856.

5 0
3 years ago
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