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Pie
3 years ago
5

PLS PLS PLS PLS PLS PLS PLS HELP ME OUT THERE IS A PHOTO ATTACHED PLS ITS EASY I THINK FOR U PLS

Mathematics
1 answer:
deff fn [24]3 years ago
3 0
No. 1.5 is a whole number while 1.5% is a percent
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Can someone tell me whats 3\4x5\6 is im dum
Anastaziya [24]

Answer:

15/24

Step-by-step explanation:

hope this helps u.

4 0
3 years ago
Read 2 more answers
Write an equation for the parabola whose vertex is at (4, 12) and which passes through (5, 21)
laiz [17]

Answer:

y - 12 = 9(x - 4)

Step-by-step explanation:

The vertex (h, k) is (4, 12) and the point (5, 21) is on the graph.  Assuming that this is a vertical parabola, opening up (because the coordinate 21 is greater than the coordinate 12), we insert the knowns into  y - k = a(x - h)^2, obtaining

21 - 12 = a(5 - 4), or  9 = a.  With a known, we can write the desired equation:

y - 12 = 9(x - 4)

8 0
3 years ago
Can anyone help me on this question please.​
STatiana [176]
The answer is 72.
You can figure this out using the Pythagorean theorem: C (78) squared - A (30) squared = B squared though since you already know the longest side.
78 x 78 = 6084
30 x 30 = 900
6084-900= 5184
The square root of 5184 is 72.
5 0
3 years ago
A basin is filled by two pipes in 12 minutes and 16 minutes respectively. Due to the obstruction of water flow after the two pip
olasank [31]

Answer:

The time duration of the two pipes restricted flow before the flow became normal is 4.5 minutes

Step-by-step explanation:

The given information are;

The time duration for the volume, V, of the basin to be filled by one of the pipe, A, = 12 minutes

The time duration for the volume, V, of the basin to be filled by the other pipe, B, = 16 minutes

Therefore, the flow rate of pipe A = V/12

The flow rate of pipe B = V/16

Due to the restriction, we have;

The proportion of its carrying capacity the first pipe, A, carries = 7/8 of the carrying capacity

The proportion of its carrying capacity the second pipe, B, carries = 5/6 of the carrying capacity

Whereby the tank is filled 3 minutes after the restriction is removed, we have;

\dfrac{7}{8} \times \dfrac{V}{12} \times t + \dfrac{5}{6} \times \dfrac{V}{16} \times t +  \dfrac{V}{12} \times 3 + \dfrac{V}{16} \times 3 = V

Simplifying gives;

\dfrac{(2\cdot t +7) \cdot V}{16}  = V

2·t + 7 = 16

t = (16 - 7)/2 = 4.5 minutes

Therefore, it took 4.5 seconds of the restricted flow before the the flow of water in the two pipes became normal

7 0
3 years ago
Read 2 more answers
The graph shows two lines, A and B.
Galina-37 [17]

Hello!

The solution is where the lines intersect. As you can see, they only intersect at one point.

A) It as one solution.

To find our solution, we just see what the point is they intersect at.As you can see, they intersect at (4,4).

B) (4,4)

I hope this helps!


5 0
3 years ago
Read 2 more answers
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