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3 years ago

14

Find y when x=15 if y=6 when x=30

2 answers:

soldier1979 [14.2K]3 years ago

6 0

If y = 6 when x = 30

30/15 = 2

So 6/2 = 3

Answer : when x = 15, y = 3

BigorU [14]3 years ago

3 0

You haven't told us the relationship between 'x' and 'y'. Maybe y is always 1/5 of x. Then y=3. Maybe y is always 24 less than x. Then y is -9. Maybe y is always 6 no matter what x is. / / / You gave us one point on the line ... not enough to tell what any other point is.

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How to find the missing numbers in two digit division

abruzzese [7]

Answer:

Divide the first number of the dividend (or the two first numbers if the previous step took another digit) by the first digit of the divisor. Write the result of this division in the space of the quotient. Multiply the digit of the quotient by the divisor, write the result beneath the dividend and subtract it.Jun

Step-by-step explanation:

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3 years ago

Find the slope of the line. y = 5/3x + 4

ioda

Answer:

slope= 5/3

Step-by-step explanation:

y=mx+b

slope=m

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7 0

3 years ago

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A mars rover traveled from point a to point b at a speed of 4 cm/sec. Worsening conditions during the return trip caused the rov

miskamm [114]

Using a system of linear equations, the distance between points A and B is 6000 cm

Initial speed = 4cm/sec

Time taken = Distance / speed

Let ; distance = d

<u>To</u><u> </u><u>time</u><u> </u><u>:</u><u> </u>

<u>t</u> = d / 4
<em>4t = d ______(1)</em>

<u>Fro</u><u> </u><u>time</u><u> </u><u>:</u><u> </u>

(t + 15 × 60) = d / 2.5

2.5(t + 900) = d

<em>2.5t + </em><em>2250</em><em> = d ______(2)</em>

Equate (1) and (2)

4t = 2.5t + 2250

4t - 2.5t = 2250

1.5t = 2250

t = 1500 seconds

From (1) :

d = 4t

d = 4(1500)

d = 6000 cm

Therefore, the distance from point A to B is 6000 cm

Learn more : brainly.com/question/14000187

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2 years ago

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Show that y=cos(t)y=cos(t) is a solution to (dydt)2=1−y2(dydt)2=1−y2. Enter your answers below in terms of the independent varia

GrogVix [38]

Answer:

$(\frac{dy}{dt})^2=sin^2t$

Step-by-step explanation:

$y=cost$

DE : $(\frac{dy}{dt})^2=1-y^2$

If y is a solution of given DE then it satisfied the DE.

Differentiate w.r.t t

$\frac{dy}{dt}=-sint$

Using the formula

$\frac{d(cosx)}{dx}=-sinx$

LHS: $(\frac{dy}{dt})^2=(-sint)^2=sin^2t$

RHS

$1-y^2=1-cos^2t=sin^2t$

By using the formula

$sin^2t=1-cos^2t$

LHS=RHs

Hence, y is a solution of given DE

$(\frac{dy}{dt})^2=sin^2t$

7 0

3 years ago

Of the 480 flowers in a shop, 30% are lillies ,45% are orchids, and the rest are roses. How many roses are there in the shop?

Flura [38]

30 + 45 = 75

100 - 75 = 25

25% = 0.25

Multiply:

0.25 × 480 = 120

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3 years ago

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