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bazaltina [42]
2 years ago
10

Which table represents a linear function?

Mathematics
2 answers:
ladessa [460]2 years ago
6 0

Answer:

(0,3), (1,1), (2,-1), (3,-3)

Step-by-step explanation:

<em>good luck, i hope this helps :)</em>

Kisachek [45]2 years ago
5 0

Answer:

D

Step-by-step explanation:

You might be interested in
Show that the line integral is independent of path by finding a function f such that ?f = f. c 2xe?ydx (2y ? x2e?ydy, c is any p
Juli2301 [7.4K]
I'm reading this as

\displaystyle\int_C2xe^{-y}\,\mathrm dx+(2y-x^2e^{-y})\,\mathrm dy

with \nabla f=(2xe^{-y},2y-x^2e^{-y}).

The value of the integral will be independent of the path if we can find a function f(x,y) that satisfies the gradient equation above.

You have

\begin{cases}\dfrac{\partial f}{\partial x}=2xe^{-y}\\\\\dfrac{\partial f}{\partial y}=2y-x^2e^{-y}\end{cases}

Integrate \dfrac{\partial f}{\partial x} with respect to x. You get

\displaystyle\int\dfrac{\partial f}{\partial x}\,\mathrm dx=\int2xe^{-y}\,\mathrm dx
f=x^2e^{-y}+g(y)

Differentiate with respect to y. You get

\dfrac{\partial f}{\partial y}=\dfrac{\partial}{\partial y}[x^2e^{-y}+g(y)]
2y-x^2e^{-y}=-x^2e^{-y}+g'(y)
2y=g'(y)

Integrate both sides with respect to y to arrive at

\displaystyle\int2y\,\mathrm dy=\int g'(y)\,\mathrm dy
y^2=g(y)+C
g(y)=y^2+C

So you have

f(x,y)=x^2e^{-y}+y^2+C

The gradient is continuous for all x,y, so the fundamental theorem of calculus applies, and so the value of the integral, regardless of the path taken, is

\displaystyle\int_C2xe^{-y}\,\mathrm dx+(2y-x^2e^{-y})\,\mathrm dy=f(4,1)-f(1,0)=\frac9e
8 0
3 years ago
Please help asap will give brainliest if correct.
professor190 [17]

Answer:

x¹²,8x⁴,6x,2x,1

Step-by-step explanation:

x²×x⁶×x⁴=x¹²

x^4(8) =8x⁴

x^1(6) =6x

x^1(2) =2x

x^0 = 1

3 0
3 years ago
Please help solve for x..
aalyn [17]

Answer:

x = 1 or x = -1

Step-by-step explanation:

Given equation:

x^{100}-4^x \cdot x^{98}-x^2+4^x=0

Factor out -1:

\implies -1(-x^{100}+4^x \cdot x^{98}+x^2-4^x)=0

Divide both sides by -1:

\implies -x^{100}+4^x \cdot x^{98}+x^2-4^x=0

Rearrange the terms:

\implies 4^x \cdot x^{98}-4^x-x^{100}+x^2=0

\textsf{Apply exponent rule} \quad a^{b+c}=a^b \cdot a^c \quad \textsf{to }x^{100}:

\implies 4^x \cdot x^{98}-4^x-x^{98}x^2+x^2=0

Factor the first two terms and the last two terms separately:

\implies 4^x(x^{98}-1)-x^2(x^{98}-1)=0

Factor out the common term (x^{98}-1) :

\implies (4^x-x^2)(x^{98}-1)=0

<u>Zero Product Property</u>:  If a ⋅ b = 0 then either a = 0 or b = 0 (or both).

Using the <u>Zero Product Property</u>, set each factor equal to zero and solve for x (if possible):

\begin{aligned}x^{98}-1 & = 0 & \quad \textsf{or} \quad \quad4^x-x^2 & = 0 \\x^{98} & =1 & 4^x & = x^2 \\x & = 1, -1 & \textsf{no}& \textsf{ solutions for } x \in \mathbb{R}\end{aligned}

Therefore, the solutions to the given equation are: x = 1 or x = -1

Learn more here:

brainly.com/question/27751281

brainly.com/question/21186424

3 0
1 year ago
Translate to algebraic expressions
galben [10]
1. x+½
2. 82-x
3. 4(x+3/10)
4. 2x-21
5.2x²
6. ⅓(x+53)

7 0
3 years ago
please help, I do not know how to do this at all! A restaurant has a large goldfish pond. Suppose that an inlet pipe and a hose
Ne4ueva [31]

Answer:

H = 20.5 hours

I = 19.5 Hours

Step-by-step explanation:

Start by creating a system.

I = time which the inlet pipe takes alone to fill the pond

H = time which the hose takes alone to fill the pond

10/I + 10/H = 10

H - I = 1

H = 20.5 hours

I = 19.5 Hours

8 0
3 years ago
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