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3 years ago

I NEED HELP ASAP PLEASE HELP ME

Mathematics

1 answer:

Ket [755]3 years ago

3 0

The volume of a rectangular prism is (base)(height).
Let the base be B and the height H.
Then V=BH.

If V=36 in^3 and H=6 in, then the area of the base B is V/H,
or
B = [36 in^3] / [6 in] = 6 in^2 (6 square inches)

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Maya can run 18 miles in 3 hours, and she can bike 18 miles in 2 hours.

Aloiza [94]

Answer:

Step-by-step explanation:

if it is two hours then half of it is 9

so 18 + 9 = 27 which is how many miles she biked

6 is the number of miles she ran

so u times it by 1.5

27 + 9 = 36

4 0

3 years ago

Read 2 more answers

Harold and his friend both enjoy running long distances.Yesterday Harold ran 8 2/4 miles and his friend ran 4 3/4 miles. How man

andriy [413]

Answer:

Harold ran $3\frac{3}{4}\ miles$ more than his friend.

Step-by-step explanation:

Given:

Number of miles Harold ran = $8\frac{2}{4}\ miles$

$8\frac{2}{4}\ miles$ can be Rewritten as $\frac{34}{4}\ miles$

Number of miles Harold ran = $\frac{34}{4}\ miles$

Number of miles his friend ran = $4\frac{3}{4}\ miles$

$4\frac{3}{4}\ miles$ can be Rewritten as $\frac{19}{4}\ miles$

Number of miles his friend ran = $\frac{19}{4}\ miles$

We need to find number of miles Harold ran more than his friend.

Solution:

Now we can say that;

To find the number of miles Harold ran more than his friend we need to subtract Number of miles his friend ran from Number of miles Harold ran.

framing in equation form we get;

the number of miles Harold ran more than his friend = $\frac{34}{4}-\frac{19}{4} =\frac{34-19}{4} = \frac{15}{4}\ miles$

$\frac{15}{4}\ miles$ can be Rewritten as $3\frac{3}{4}\ miles$

the number of miles Harold ran more than his friend = $3\frac{3}{4}\ miles$

Hence Harold ran $3\frac{3}{4}\ miles$ more than his friend.

4 0

3 years ago

I need help with this Khan plz

tigry1 [53]

Find the constant of proportionality

8 0

3 years ago

Given the sequence 8, 16, 32, 64, ..., which expression would give the thirteenth term?

mrs_skeptik [129]

8, 16, 32, 64,…
×2 ×2 ×2

$a_{n} = a_{1} * r^{n - 1}$
$a_{n} = 8 * 2^{13 - 1}$
$a_{n} = 8 * 2^{12}$
$a_{n} = 8 * 4096$
$a_{n} = 32768$

   First Term: 8
      Second Term: 16
      Third Term: 32
      Fourth Term: 64
       Fifth Term: 128
      Sixth Term: 256
   Seventh Term: 512
   Eighth Term: 1024
   Ninth Term: 2048
      Tenth Term: 4096
   Eleventh Term: 8192
   Twelfth Term: 16384
Thirteenth Term: 32768

$The\ expression\ that\ would\ give\ the\ thirteenth\ term\ of\ the\ problem\ would\ be\ the\ equation\ of\ the\ geometric\ sequence,\ which\ is\ equal\ to\ a_{n} = a_{1} * r^{n - 1}.$

5 0

3 years ago

Read 2 more answers

What is the domain of the relation {(2, 8), (0, 8), (–1, 5), (–1, 3), (–2, 3)}?

olga2289 [7]

Hello,

dom f={-2,-1,0,2}
Range={3,5,8}

3 0

3 years ago