How can right triangles be similar based on their angles
1 answer:
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Answer:
y = sin(x- pi/2)
Step-by-step explanation:
Please see the attached image to see your graphs.
By simple inspection we can see that the sine is shifted pi/2 to the right.
We know this because sines are periodic functions with a period T = 2*pi
We can also see that the maximum point of the graph (y = 1) got shifted by a fourth of the period.
And finally, since we want to shift the graph to the right, we need to substract from the argument of the sine term.
