The ordered pairs of the equation y = 3^x are (0,1), (1,3) and (2,9)
<h3>How to type the ordered pairs?</h3>
The equation is given as:
y = 3^x
Let x = 0, 1 and 2
y = 3^0 = 1
y = 3^1 = 3
y = 3^2 = 9
So, we have the following ordered pairs (0,1), (1,3) and (2,9)
Hence, the ordered pairs of the equation y = 3^x are (0,1), (1,3) and (2,9)
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Step-by-step explanation:
3(x - 4y) - 2(y + 7x)
= 3x - 12y - 2y - 14x
= 3x -14x -12y -2y
= -11x -14y
Answer:
Step-by-step explanation:
let the number=x
4>3x-5
9>3x
3x<9
x<3
Answer:
m/3=<1
Step-by-step explanation:
Answer:
Step-by-step explanation:
Note that it is a triangle's measurement = 180°
You are solving for x. Set all the angles = 180°
73 + 8x + 4 + 8y - 7 = 180
Simplify. Combine like terms
73 + 4 - 7 + 8x + 8y = 180
70 + 8x + 8y = 180
Solve for x. Subtract 8y and 70 from both sides
8x + 8y (-8y) + 70 (-70) = 180 (-8y) - (70)
8x = 180 - 70 - 8y
8x = 110 - 8y
Isolate the x. Divide 8 from both sides
(8x)/8 = (110 - 8y)/8
x = 13.75 - y
x = 13.75 - y is your equation you will use to solve for x when you know what y is.
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