Mode = number which appears the most
The mode for your question is 5
Answer:
Ok, here we have two points A and B.
The shorter object will be the second option, AB with a line on top, this is a segment, so the length of this object is equal to the distance between A and B.
The next one is AB with an arrow pointing to the right, this is ray, is a line that starts in A and passes through B, and continues infinitely.
The third will be the bottom option, AB with a double-arrow on top, this is the notation for a line that passes through A and B, and it extends to infinity in both directions.
Answer:
The sequence is:
10, 30, 50, 70, 90.....................
Step-by-step explanation:
We have,
First term (a) = 10
Common difference (d) = ?
Sum of first 5 terms (
) = 250
or, ![\frac{n}{2} [{2a+(n-1)d}] = 250](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B2%7D%20%5B%7B2a%2B%28n-1%29d%7D%5D%20%3D%20250)
or, ![\frac{5}{2} [2*10 + 4d]=250](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%7D%20%5B2%2A10%20%2B%204d%5D%3D250)
or, ![\frac{5}{2} * 4[5+d]=250](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%7D%20%2A%204%5B5%2Bd%5D%3D250)
or, 10(5 + d) =250
or, 5 + d = 25
∴ d = 20
Now,
2nd term = a + d = 10 + 20 = 30
3rd term = a + 2d = 10 + 2*20 = 10 + 40 = 50
4th term = a + 3d = 10 + 3*20 = 10 + 60 = 70
5th term = a + 4d = 10 + 4*20 = 10 + 80 = 90
Answer:
<h2>
<em><u>B. 20% because he only got 400 back</u></em><em><u> </u></em></h2>
<em>Pls</em><em> </em><em>Mark</em><em> </em><em>me</em><em> </em><em>as</em><em> </em><em>brainliest</em><em> </em>
