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3 years ago

Which expression are equivalent to the one below 36^x /6^x

Mathematics

1 answer:

Ostrovityanka [42]3 years ago

8 0

Step-by-step explanation:

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Geometry help please!!!

julia-pushkina [17]

Before we begin, let's identify what kind of angles these are and are they related in any way?

These angles are both acute and they are both corresponding angles.
Corresponding angles are equal to each other, and we can use this fact to our advantage.

Since they are equal to each other, we can set the equations of 1 and 2 equal to each other. Like so,

1 = 2
83 - 2x = 92 - 3x

Now, we can solve for X by isolating it on one side.

83 - 2x = 92 - 3x

Add 3x to each side: (This basically moves the X on the right side to the left.)
83 - 2x + 3x = 92 - 3x + 3x
83 + x = 92

Subtract 83 on each side to isolate the X.
83 + x - 83 = 92 - 83
x = 92 - 83
x = 9

Therefore, X equals 9. To check our work, we can substitute X for 9.
83 - 2(9) = 92 - 3(9)
83 - 18 = 92 - 27
65 = 65 -
TRUE

So to conclude, Angle 1 is 65 degrees, Angle 2 is 65 degrees, and X equals 9.

Hope I could help you out!
If my answer is incorrect, or I provided an answer you were not looking for, please let me know. However, if my answer is explained well and correct, please consider marking my answer as Brainliest! :)

Have a good one.
God bless!

7 0

3 years ago

Determine the product.

Andrei [34K]

The final expression in standard form will be 1.601 * 10^9

<h3>Indices and expoenets</h3>

Given the expression as shown:

800.5 * (2*10^6)

This can be further simplified as:

$= 8.005 * 10 ^2 * 2 * 10^6\\= 16.01 * 10^{2+6}\\= 16.01 * 10^8$

The final expression in standard form will be 1.601 * 10^9

Learn more on indices here: brainly.com/question/10339517

3 0

3 years ago

Read 2 more answers

HELP NOW!! I’m desperate. I’ll give extra points and brainliest. I’m so lost. *loud crying*

iragen [17]

Square the top and the bottom. To get 7/11.

8 0

3 years ago

2 tan 30°<br>II<br>1 + tan- 300

shusha [124]

Question:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Answer:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

Step-by-step explanation:

Given

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Required

Simplify

In trigonometry:

$tan(30^{\circ}) = \frac{1}{\sqrt{3}}$

So, the expression becomes:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}$

Simplify the denominator

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}$

Express the fraction as:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} / \frac{4}{3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} * \frac{3}{4}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{1}{\sqrt 3} * \frac{3}{2}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3}$

Rationalize

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3\sqrt{3}}{2* 3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\sqrt{3}}{2}$

In trigonometry:

$sin(60^{\circ}) = \frac{\sqrt{3}}{2}$

Hence:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

3 0

3 years ago

I don't get this problem please help me

faltersainse [42]

To find the area of any rectangle you multiply length times width.
8,1/2*11
17/2*11/1
187/2
93.5 or 93, 1/2.
For the second bit you just divide 1000 by 93.5. 1000/93.5=10.7 So ten pieces. Hope this helps! <span />

8 0

3 years ago