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Iteru [2.4K]
3 years ago
6

ASAP! The graph shows outdoor temperatures (F) recorded one fall evening in Ohio. At what rate did the temperature change during

this time interval?
A, -3F/minute

B, -4F/hour

C, -5F/minute

D, -3F/hour

Mathematics
1 answer:
babymother [125]3 years ago
8 0
Your answer would be D) -3°F/hour
Look at it this way...

47°F at 7:20pm
46°F at 7:40pm
45°F at 8:00pm
44°F at 8:20pm
43°F at 8:40pm

The temperature is going down by 1°F every 20 minutes so...

-1°F/20 minutes

Obviously there's no answer choice that says that so you'd need to change the minutes into an hour...

So an hour is 60 minutes and 60/20 = 3

So if you do 3・-1

You get the answer... -3°F/hour
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I believe it is 45.6
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3 years ago
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Stella [2.4K]

Answer:

-10

Step-by-step explanation:

the answer to the question is-10

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2 years ago
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The SHS step team is selling shs spirit t-shirts to raise money. The orange/black shirt sells for $15 and the black/white shirt
IRINA_888 [86]

Answer:

Option A)

15x + 10y \geq 1000

Step-by-step explanation:

We are given the following in the question:

Cost of orange/black shirt = $15

Cost of black/white shirt = $10

Amount of money to be raised is atleast $1000.

Let x be the amount of orange/black shirt and y be the amount of  black/white shirt.

Thus, we can write the inequality:

15x + 10y \geq 1000

That is the total cost of orange/black shirt and black/white shirt should be greater than or equal to $1000.

Thus, the correct answer is

Option A)

15x + 10y \geq 1000

8 0
3 years ago
HELP DUE NOW! BRANLIEST AND LOTS OF PONTS
Lisa [10]

Answer:

I think it’s a

Step-by-step explanation:

4 0
3 years ago
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Short Response
garik1379 [7]

Answer:

(a)2(89x+84)

(b)2(89x+84-x^2\pi)

Step-by-step explanation:

The dimensions of the larger rectangular field are:

  • Length=5x + 12; Width = 9x + 14.

The dimensions of the smaller rectangular soccer field are:

  • Length=5x; Width = 9x.

(a)Area of the part of the field that is outside the soccer field

=Area of the larger rectangular field - Area of the Soccer Field

=(5x+12)(9x+14)-5x(9x)

=(5x)(9x)+70x+108x+168-5x(9x)

=178x+168

=2(89x+84)

(b)Radius of the Semicircular Fountain =2x

From Part (a),

Area of the larger rectangular field - Area of the Soccer Field=178x+168

Area of the Semicircular Fountain =\dfrac{\pi r^2}{2} =\dfrac{\pi (2x)^2}{2} =\dfrac{4x^2\pi}{2} =2x^2\pi

Area of the Field that does not include the soccer  field or the fountain.

=Area of the larger rectangular field - Area of the Soccer Field-Area of the Semicircular Fountain

=178x+168-2x^2\pi\\=2(89x+84-x^2\pi)

8 0
3 years ago
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