2k•squared• + 7 - 15 factoring ax•squared•+bx+c

1 answer:

6 0

Calculate Δ = b^2 -4ac => Δ = 169 => k1 = 3/2; k2 = -5 => 2k^2 + 7k - 15 = 2*(k -3/2)(k+5) = (2k - 3)(k+5);

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