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dlinn [17]
3 years ago
12

WILL MARK BRAINLIEST!

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
5 0

Answer:

vt =  \sqrt{ {20}^{2} +  {17}^{2}  } \\  =  \sqrt{400  + 289 }   \\  =  \sqrt{689}  \\ vw =  \sqrt{ {vt}^{2} +  {tw}^{2}  }  \\   = \sqrt{689 +  {20}^{2} }  \\  =  \sqrt{1089}  = 33 \\

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Which table represents the statement "Brian rides a bicycle at a rate of 12 meters per second"?
goldenfox [79]

Answer: D

Step-by-step explanation: Because

1 x 12 = 12

2 x 12 = 24

3 x 12 = 36

4 0
3 years ago
Read 2 more answers
Wright Company's cash account shows a $30,100 debit balance and its bank statement shows $28,400 on deposit at the close of busi
Nat2105 [25]

Answer:

Step-by-step explanation:

30,100+28,400-230=58,040

58,040

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8 0
3 years ago
Help me please anyone I need help asap
Lera25 [3.4K]
156cm=1.56m=0.0156km
5 0
3 years ago
Can the numbers 24, 32, 42, be the lengths of the three sides of the right triangle? Explain why or why not
Musya8 [376]
No the don't add up to one eighty I'm pretty sure if not tell me
8 0
4 years ago
What is the distance to the Earth's Horizon from point P? Enter enter the decimal in the Box round only your final answer to the
Tasya [4]

Answer:

<h2>The distance to the Eath's Horizon from point P is 352.8 mi, approximately.</h2>

Step-by-step explanation:

You observe the problem from a graphical perspective with the image attached.

Notice that side x is tangent to the circle, which means is perpendicular to the radius which is equal to 3,959 mi.

We have a right triangle, that means we need to use the Pythagorean's Theorem, to find the distance to the Earth's Horizon from point P.

The hypothenuse is 3959 + 15.6 = 3974.6 mi.

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Therefore, the distance to the Eath's Horizon from point P is 352.8 mi, approximately.

4 0
4 years ago
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