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GaryK [48]
3 years ago
12

Wendy is looking over some data regarding the strength, measured in Pascals (Pa), of some rope and how the strength relates to t

he number of woven strands in the rope. The data are represented by the exponential function f(x) = 2x, where x is the number of woven strands. Explain how she can convert this equation to a logarithmic function when strength is 256 Pascals.
Mathematics
1 answer:
Zarrin [17]3 years ago
4 0
F(x)=2^x
Lets say f(x) is y
Y=2^x
Take log both side
Log(y)=log(2^x)
Logy=log2^256
logy=256×log2
By Log property
Logy=77.06

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Step-by-step explanation:

7 0
3 years ago
What percent of 80 is 50? Show your work.
Usimov [2.4K]

            50*2= 100

               So 50 is one half of One hundred and if we use 100 divided by 2 to get 50 then we need to do 80 / 2 which will give us 40.

4 0
3 years ago
Which numbers in set B are elements of both even numbers and multiples of 7? B = {-7, -4, 2, 14, 21, 34, 42}
Dmitriy789 [7]

Answer:

14, 42

Step-by-step explanation:

-7 is only a multiple of 7

-4 is only even

2 is only even

21 is only a multiple of 7

34 is only even

3 0
3 years ago
Please help me !!!!!!!!!!
maria [59]

Answer:

EF=6

Step-by-step explanation:

In this problem, one is given a circle with two secants (that is a line that intersects a circle at two points). One is given certain measurements, the problem asks one to find the unknown measurements.

The product of the lengths theorem gives a ratio between the lengths in the secants. Call the part of the secant that is inside the circle (inside), and the part of the secant between the exterior of the circle and the point of intersection of the secants (outside). The sum of (inside) and (outside) make up the entire secant, call this measurement (total). Remember, there are two secants, (secant_1) and (secant_2) in this situation. With these naming in mind, one can state the product of the length ratio as the following:

\frac{total_1}{outside_2}=\frac{total_2}{outside_1}

Alternatively, one can state it like the following ratio:

\frac{inside_1+ouside_1}{outside_2}=\frac{inside_2+outside_2}{outside_1}

Apply this ratio to the given problem, substitute the lengths of the sides of the secants in and solve for the unknown.

\frac{EF+FG}{HG}=\frac{SH+HG}{FG}

\frac{2x+4}{5}=\frac{x+5}{4}

Cross products, multiply the numerator and denominators of opposite sides of the fraction together,

\frac{2x+4}{5}=\frac{x+5}{4}

4(2x+4)=5(x+5)

Simplify,

4(2x+4)=5(x+5)

8x+16=5x+25

Inverse operations,

8x+16=5x+25

3x+16=25\\3x=9\\x=3

Substitute this value into the equation given for the measure of (EF),

EF=2x\\x=3\\\\EF=2x\\=2(3)\\=6

6 0
3 years ago
Pirate Jack has an equal number of gold and silver coins. If Pirate Jack splits all of his coins into 7 equal piles for his parr
Tcecarenko [31]

Answer:

The least possible number of coins the Pirate has = 81

Step-by-step explanation:

Given:

Pirate Jack has equal number of gold and silver coins.

When the pirate splits the coins into 7 equal piles he has 4 coins left.

When the pirate splits the coins into 11 equal piles he has 4 coins left.

Every pile has at least 1 coin.

To find the least possible number of coins Pirate Jack has.

Solution:

In order to find the least possible number of coins pirate Jack has, we must find the least common multiple of the number of piles the coins are split into.

So, the least common multiple of 7 and 11 can be found by listing the multiples.

7= 7,14,21,28...............,77

11=11,22,33,44,55,66,77

So, we find the least common multiple of 7 and 11 is 77.

Number of coins left = 4

Total number of coins the pirate must have = 77+4 =81

We can check the answer by dividing 81 by 7 and 11. I both cases we get remainder = 4.

So, the least possible number of coins the pirate has = 81

6 0
4 years ago
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