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vovikov84 [41]
3 years ago
13

PLEASE answer this one.. I'm down to last answer.. I wanna sleep

Mathematics
1 answer:
Vinvika [58]3 years ago
6 0

that's correct, what you've put in the boxes. :)



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Factorise a squared - b squared
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(a-b)(a+b) because when you reverse the sum you do axa and ax-b xx
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I need help please and thank you
Sedaia [141]

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20 hours

Step-by-step explanation:

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three different accounts are described below. order the accounts to their values after 10 years, from greatest to least.
Sedbober [7]

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You deposit $800 in an account that earns 7.5% annual interest compounded quarterly.

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The solution is <br><br> u = ?
Tpy6a [65]

Answer:

u = (b/hn)

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The inverse!!

3 0
2 years ago
How many permutations are there of the letters in the words (a) TRISKAIDEKAPHOBIA (fear of the number 13)? (b) FLOCCINAUCINIHILI
zubka84 [21]

Answer: Hello!

Let's start with the word TRISKAIDEKAPHOBIA wich has 17 letters (some of them repeat, but it does not matter in this problem)

We want to know how many permutations we can do with 17 letters: then think this way, Lets compose a word. The first letter of this word has 17 options, the second letter of the word has 16 options (you already took one of the set) the third letter of the word has 15 options, and so on.

The total number of permutations is the product of the number of options that you have for each letter, this is:

17*16*15*14*....*3*2*1 = 17! = 3.6e+14

(b) FLOCCINAUCINIHILIPILIFICATION now we have 30 letters in total, using the same reasoning as before, here we have 30! permutations; this is

30! = 2.65e+32

(c) PNEUMONOULTRAMICROSCOPICSILICOVOLCANOCONIOSIS: now there are 47 letters.

then P = 47! = 2.59e+59

(d) DERMATOGLYPHICS: here are 18 letters, then:

p = 18! = 6.4e+15

6 0
3 years ago
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