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Sladkaya [172]
3 years ago
8

A rally car race course covers 515.97 miles. The winning car completed the course in 6.5 hours. What was the average speed of th

e winning car?
Mathematics
2 answers:
evablogger [386]3 years ago
4 0

Answer:

79.38 miles per hour

Step-by-step explanation:

average speed =  miles covered / hours

= 515.97 / 6.5

=  79.38

fomenos3 years ago
3 0

Answer:    79.38 miles per hour

Step-by-step explanation:

Given : Distance covered by rally car race course = 515.97 miles

Time taken to complete the course by winning car = 6.5 hours

The average speed of the winning car = ( Distance covered by rally car race course) ÷  (Time taken to complete the course by winning car)

= (515.97)÷ (6.5) miles per hour

= 79.38 miles per hour

Hence, the average speed of the winning car =  79.38 miles per hour.

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A box contains 3 coins. One coin has 2 heads and the other two are fair. A coin is chosen at random from the box and flipped. If
Blababa [14]

Answer: Our required probability is \dfrac{1}{2}

Step-by-step explanation:

Since we have given that

Number of coins = 3

Number of coin has 2 heads = 1

Number of fair coins = 2

Probability of getting one of the coin among 3 = \dfrac{1}{3}

So, Probability of getting head from fair coin = \dfrac{1}{2}

Probability of getting head from baised coin = 1

Using "Bayes theorem" we will find the probability that it is the two headed coin is given by

\dfrac{\dfrac{1}{3}\times 1}{\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times 1}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{1}{6}+\dfrac{1}{6}+\dfrac{1}{3}}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{2}{3}}\\\\=\dfrac{1}{2}

Hence, our required probability is \dfrac{1}{2}

No, the answer is not \dfrac{1}{3}

5 0
3 years ago
4n+6b-8 what are the terms
expeople1 [14]
4n, 6b, and -8 are the terms
8 0
3 years ago
Read 2 more answers
Find a pair of square numbers which give a difference of 39
nadya68 [22]
64-25=39 All the square numbers are 1,4,9,16,25,36,49,64,81,100
5 0
4 years ago
Just this please helppp
Murrr4er [49]

The height of the <em>water</em> depth is h = 14 + 6 · sin (π · t/6 + π/2), where t is in hours, and the height of the Ferris wheel is h = 21 + 19 · sin (π · t/20 - π/2), where t is in seconds. Please see the image to see the figures.

<h3>How to derive equations for periodical changes in time</h3>

According to the two cases described in the statement, we have clear example of <em>sinusoidal</em> model for the height as a function of time. In this case, we can make use of the following equation:

h = a + A · sin (2π · t/T + B)     (1)

Where:

  • a - Initial position, in meters.
  • A - Amplitude, in meters.
  • t - Time, in hours or seconds.
  • T - Period, in hours or seconds.
  • B - Phase, in radians.

Now we proceed to derive the equations for each case:

Water depth (u = 20 m, l = 8 m, a = 14 m, T = 12 h):

A = (20 m - 8 m)/2

A = 6 m

a = 14 m

Phase

20 = 14 + 6 · sin B

6 = 6 · sin B

sin B = 1

B = π/2

h = 14 + 6 · sin (π · t/6 + π/2), where t is in hours.

Ferris wheel (u = 40 m, l = 2 m, a = 21 m, T = 40 s):

A = (40 m - 2 m)/2

A = 19 m

a = 21 m

Phase

2 = 21 + 19 · sin B

- 19 = 19 · sin B

sin B = - 1

B = - π/2

h = 21 + 19 · sin (π · t/20 - π/2), where t is in seconds.

Lastly, we proceed to graph each case in the figures attached below.

To learn more on sinusoidal models: brainly.com/question/12060967

#SPJ1

5 0
2 years ago
Help me pls y=(1+x)m
muminat
What is it that we need to find?
7 0
3 years ago
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