Answer:
1 is a solution, 2 isnt
Step-by-step explanation:
For number 1,both problems are true with the given values of x and y, but with number 2, oy the second problem is true
At the point when Hannah takes her first sweet from the sack, there is a 6/n chance it is orange.
This is because that there are 6 orange desserts and n desserts altogether.
When Hannah takes out her second sweet, there is a 5/(n-1) chance that it is orange.
This is because there are just 5 orange desserts let alone for an aggregate of n-1 desserts.
The possibility of getting two orange desserts in succession is the main likelihood increased by the second one: 6/n x 5/n–1
The question lets us know that the shot of Hannah getting two orange desserts is 1/3.
So: 6/n x 5/n–1 = 1/3
Now, rearrange this problem.
(6x5)/n(n-1) = 1/3
This gets to be:
30/(n² – n) = 1/3
Times by 3 on both sides:
90/(n² – n) = 1
What's more, doing likewise with (n² – n):
So (n² – n) = 90
Our answer is: n² – n – 90 = 0
Answer:
the normal x is three and the red x is negative three
Step-by-step explanation:
Answer:
Step-by-step explanation:
no, as 8 is not <2
10+8/2-4
PEMDAS
parenthasese
exxonents
multiplication or division
addiotn or subtration next
10+8/2-4
8/2 first
4
10+4-4
add
10+4=14
minus
14-4=10
answer is 10
