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Arturiano [62]
2 years ago
5

F) m(4+p) +p(3 + m)

Mathematics
2 answers:
ipn [44]2 years ago
7 0

\bold{\huge{\pink{\underline{ Solutions }}}}

  • <u>Here</u><u>, </u><u> </u><u>we </u><u>have </u><u>to </u><u>expand </u><u>the </u><u>given </u><u>expression</u><u>s</u><u> </u><u>and </u><u>simplify </u><u>each </u><u>one </u><u>of </u><u>them</u>

<h3><u>Solution</u><u> </u><u>1</u><u> </u><u>:</u><u>-</u></h3>

\bold{m(4 + p) + p( 3 + m) }

\sf{4×m + m× p + p×3+ m × p}

\sf{4m + mp + 3p + mp }

\bold{\red{ 2mp + 4m + 3p}}

Hence, Your answer is 2mp + 4m + 3p

<h3><u>Solution </u><u>2</u><u> </u><u>:</u><u>-</u></h3>

\bold{4r(3+ 4p) + 3p( 8 - r) }

\sf{4r× 3+ 4r × 4p + 3p× 8 - 3p × r}

\sf{12r + 16rp + 24p - 3rp }

\sf{12r + 24p + 13rp }

\bold{\red{13rp + 24p + 12r }}

Hence, your answer is 13rp + 24p + 12r

<h3><u>Solution </u><u>3</u><u> </u><u>:</u><u>-</u></h3>

\bold{(3 + 2h)(5 + 3h )}

\sf{3(5 + 3h) + 2h(5 + 3h }

\sf{15 + 9h + 10h + 6h² }

\sf{15 + 19h + 6h²}

\bold{\red{6h² + 19h + 15}}

Hence, your answer is 6h² + 19h + 15

<h3><u>Solution </u><u>4</u><u> </u><u>:</u><u>-</u></h3>

\bold{(3 + 4y)(5y - 1 ) }

\sf{3(5y - 1 ) + 4y(5y - 1) }

\sf{15y - 3 + 20y² - 4y }

\sf{11y - 3 + 20y²}

\bold{\red{20y² + 11y - 3 }}

Hence, your answer is 20y² + 11y - 3

<h3><u>S</u><u>olution </u><u>5</u><u> </u><u>:</u><u>-</u></h3>

\bold{(2n - 3p )(3p - 2m ) }

\sf{2n(3p - 2m) -3p(3p - 2m) }

\sf{ 6np - 4nm - 9p² + 6mp }

\bold{\red{- 9p² - 6mp - 4nm + 6np }}

Hence, your answer is - 9p² - 6mp - 4nm + 6np

Agata [3.3K]2 years ago
7 0

Answer:

f) 4m + 2mp + 3p

g) 12r + 13pr + 24p

h) 6h^2 + 19h + 15

i) 20y^2 + 11y - 3

j) -9p^2 - 4mn + 4mp + 6np

Step-by-step explanation:

f) m(4+p) +p(3 + m)

  m(4) m(p) + p(3) + p(m)

  4m + mp + 3p + mp

  4m + 2mp + 3p

g) 4r(3 + 4p) + 3p(8-r)

   4r(3) + 4r(4p) + 3p(8) + 3p(-r)

   12r + 16pr + 24p + -3pr

   12r + 13pr + 24p

h) (3 + 2h)(5 +3h)

   3(5 +3h) + 2h(5 +3h)

   15 + 9h + 10h + 6h^2

   6h^2 + 19h + 15

i) (3 + 4y)(5y - 1)

  3(5y - 1) + 4y(5y - 1)

  15y - 3 + 20y^2 - 4y

  20y^2 + 11y - 3

j) (2n - 3p)(3p - 2m)

  2n(3p - 2m) + -3p(3p - 2m)

  6np - 4mn + -9p^2 +4mp

  -9p^2 - 4mn + 4mp + 6np

Hope this helps!

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Answer:

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hope this helps :)

Step-by-step explanation:

14x + 12y = 52

12x + 12y = 48

^^^ this is an inequality that we can make.  

x stands for pushups

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if we subtract the second equation from the first, we get

2x = 4

x = 2

now we can place x in one of the equations to solve for y

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Answer:

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