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trapecia [35]
3 years ago
7

Which shows the image of rectangle ABCD after rotation (x,y) (-y,x)​

Mathematics
2 answers:
OLEGan [10]3 years ago
5 0

Answer:

It's the first one

Step-by-step explanation:

Just took did it on edge

bulgar [2K]3 years ago
4 0

Answer:

The first one

Step-by-step explanation:

the C y value is 4 and the first one's C' x value is -4

proving x=>-y

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What is distributive property? <br>​
Svet_ta [14]

Answer:

To distribute means to divide something or give a share or part of something. For example, for the problem <em>4</em><em>(</em><em>6</em><em>+</em><em>2</em><em>)</em>, you would use the distributive property and distribute the 4. Making the end result, <em>2</em><em>4</em><em>+</em><em>8</em>.

5 0
2 years ago
Which of the following linear inequalities matches the given graph below?
frozen [14]

Answer:

O y > 4

Step-by-step explanation:

The dotted line indicates the line is not part of the inequality, and it is clearly greater than 4.

8 0
2 years ago
Question :-
DochEvi [55]

\qquad\qquad\huge\underline{{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \:  \bigg( \dfrac{1}{ \sqrt{7 +  \sqrt{5} } }  +  \sqrt{7 +  \sqrt{5} } \bigg) {}^{2}

\qquad \sf  \dashrightarrow \:  \bigg( \dfrac{1}{ \sqrt{7 +  \sqrt{5} } } \bigg ) {}^{2}  +  \bigg( \sqrt{7 +  \sqrt{5} } \bigg) {}^{2}  + 2 \cdot \dfrac{1}{ \sqrt{7 +  \sqrt{5} } }  \cdot \sqrt{7 +  \sqrt{5} }

\qquad \sf  \dashrightarrow \: \dfrac{1}{7 +  \sqrt{5} }  + 7 +  \sqrt{5}  + 2

\qquad \sf  \dashrightarrow \: \dfrac{49 + 7 \sqrt{5} + 7 \sqrt{5} + 5 + 14 + 2 \sqrt{5}   }{7 +  \sqrt{5} }

\qquad \sf  \dashrightarrow \: \dfrac{68+ 16 \sqrt{5}    }{7 +  \sqrt{5} }

5 0
1 year ago
CAN SOMEONE HELP ME WITH THIS MATH QUESTION ITS ABOUT TRANSLATION
earnstyle [38]

Answer:

(- 4, 1 )

Step-by-step explanation:

A translation (x + 1), y - 3 ) means add 1 to the original x- coordinate and subtract 3 from the original y- coordinate.

B = (- 5, 4 ), thus

B' = (- 5 + 1, 4 - 3 ) = (- 4, 1 )

5 0
3 years ago
Read 2 more answers
The graph of ƒ(x) = -√x is shifted to the right five units. The domain of the function represented by this graph is x ≥&gt;≤&lt;
Mars2501 [29]

Answer:

Domain = [5,∞)

Step-by-step explanation:

Given: f(x)=-\sqrt{x}

We are given that f(x) is shifted right by 5 units.

Rule : f(x)→f(x-b)

The graph f(x) shifted b units right

So, using rule : -\sqrt{x} →   -\sqrt{x-5}

So, g(x)=-\sqrt{x-5}

Now to find domain:

x-5>0

x>5

So, Domain = [5,∞).

8 0
3 years ago
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