Answer:
C I think, im not sure but sorry if im wrong
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given is a table showing the weights, in hundreds of pounds, for six selected cars. Also shown is the corresponding fuel efficiency, in miles per gallon (mpg), for the car in city driving.
Weight Fuel eff. x^2 xy y^2
X Y
28 20 784 560 400
3 22 9 66 484
35 19 1225 665 361
32 22 1024 704 484
30 23 900 690 529
29 21 841 609 441
Mean 26.16666667 21.16666667 797.1666667 549 449.8333333
Variance 112.4722222 1.805555556
Covariance -553.8611111
r -0.341120235
Correlaton coefficient =cov (xy)/S_x S_y
Covariance (x,y) = E(xy)-E(x)E(y)
The correlation coefficient between the weight of a car and the fuel efficiency is -0.341
Answer:
The equation is R = 20d + m(1)
Where R is the rental amount in dollars, d is the number of days and m is the number of miles driven
R for 3 days and 1000 miles is $1,060
Step-by-step explanation:
To properly represent the algebraic expression, we need to assign some variables.
Now, let the rental amount be R, the number of miles driven be m and the number of days rented for is d
Thus, we can say that:
R = 20d+ m(1)
Where R is rental amount, m is the number of miles driven and d is the number of days for which the truck was driven.
Now we are asked to calculate rental amount for 3 days and 1000 miles.
R = 20d + m(1)
R = 20(3) + 1000(1)
R = 60 + 1000
R = $1,060
Yes, parallelogram congruent angles theorem
Answer:
7*5*3*2^5
Step-by-step explanation:
3360/2
1680*2
840*2^2
210*2^4
105*2^5
21*5*2^5
7*5*3*2^5
