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klasskru [66]
3 years ago
12

PLS HELP WITH SCREENSHOT I WILL MARK BRAINLIEST ASAP

Mathematics
1 answer:
Alexxx [7]3 years ago
8 0
In question in and 2 it is just asking for X and 3 and 4 is just the order might be wrong depending on what your doing in math but it should be right.

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Please please help please please ASAP please I'm begging you please I have 10 minutes please y'all help please any ACE that can
Finger [1]

Answer:

RQ

Step-by-step explanation:

ML:RQ = MN:RS = LN:QS (corr side, similar triangles)

8 0
3 years ago
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Hi can someone help me with these? 5 and 6 only though
cestrela7 [59]

Answer:

5) 2z - 15 = 9

2z.=9+15

2z =24

z =12

6) 4x-2 = 62°

4x=62°+2°

4x=64°

x=16

6 0
3 years ago
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The height h of a projectile is a function of the time t it is in the air. the height in feet for t seconds is given by the func
alexgriva [62]

Domain means the values of independent variable(input) which will give defined output to the function.

Given:

The height h of a projectile is a function of the time t it is in the air. The height in feet for t seconds is given by the function

h(t)=-16t^2 + 96t

Solution:

To get defined output, the height h(t) need to be greater than or equal to zero. We need to set up an inequality and solve it to find the domain values.

To \; find \; domain:\\\\h(t) \geq0\\\\-16t^2+96t \geq  0\\Factoring \; -16t \; in \; the \; left \; side \; of \; the \; inequality\\\\-16t(t-6) \geq  0\\Step \; 1: Find \; Boundary \; Points \; by \; setting \; up \; above \; inequality \; to \; zero.\\\\t(t-6)=0\\Use \; zero \; factor \; property \; to \; solve\\\\t=0 \; (or) \; t = 6\\\\Step \; 2: \; List \; the \; possible  \; solution \; interval \; using \; boundary \; points\\(- \infty,0], \; [0, 6], \& [6, \infty)

Step \; 3:Pick \; test \; point \; from \; each \; interval \; to \; check \; whether \\\; makes \; the \; inequality \; TRUE \; or \; FALSE\\\\When \; t = -1\\-16(-1)(-1-6) \geq  0\\-112 \geq  0 \; FALSE\\(-\infty, 0] \; is \; not \; solution\\Also \; Logically \; time \; t \; cannot \; be \; negative\\\\When \; t = 1\\-16(1)(1-6) \geq  0\\80 \geq  0 \; TRUE\\ \; [0, 6] \; is \; a \; solution\\\\When \; t = 7\\-16(7)(7-6) \geq  0\\-112 \geq  0 \; FALSE\\ \; [6, -\infty) \; is \; not \; solution

Conclusion:

The domain of the function is the time in between 0 to 6 seconds

0 \leq  t \leq  6

The height will be positive in the above interval.

7 0
3 years ago
Read 2 more answers
Asap
adoni [48]
Lower Quartile-21
Upper Quartile-52
Interquartile Range- 31

Hope this helps !!
3 0
4 years ago
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Hello, happy Friday, I am just here with some geometry questions.
irga5000 [103]

Answer:

VW = 43.2

Step-by-step explanation:

First, we can see that VZ = 88 - 55 = 33.

Then by the Triangle Proportionality Theorem, we can write that:

\displaystyle \frac{55}{33}=\frac{72}{VW}

Simplify:

\displaystyle \frac{5}{3}=\frac{72}{VW}

Cross-multiply:

216=5VW

So:

\displaystyle V=\frac{216}{5}=43.2

3 0
3 years ago
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