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GREYUIT [131]
3 years ago
13

Please help me! it’s 20 points to help

Mathematics
1 answer:
Wewaii [24]3 years ago
7 0
\text {Slope of AE = Slope of AC = } \dfrac{1}{2}

\text {Slope = } \dfrac{\text {change in y}}{\text {change in x}}

\dfrac{1}{2} = \dfrac{3}{AD}

AD = 3 \times 2

AD = 6 \text { unis}

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A cylindrical can without a top is made to contain 25 3 cm of liquid. What are the dimensions of the can that will minimize the
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Answer:

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

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Given that, the volume of cylindrical can with out top is 25 cm³.

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\therefore C=2\pi r^2+2.5 \pi r \times \frac{25}{\pi r^2}

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C''=4\pi + \frac{125}{ r^3}

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4\pi r- \frac{62.5}{ r^2}=0

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\left C''\right|_{x=1.71}=4\pi +\frac{125}{1.71^3}>0

When r=1.71 cm, the metal cost will be minimum.

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h=\frac{25}{\pi\times 1.71^2}

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Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

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