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Nookie1986 [14]
3 years ago
7

How does a balanced chemical equation illustrate that mass is never lost or gained in a chemical reaction?​

Chemistry
1 answer:
monitta3 years ago
8 0

Answer:

Explanation:

Because if the equation is truly balanced, the elements on one side equal the element numbers on the other. Take a simple example.

Ba(OH)2 + 2HCl ==> BaCl2 + 2HOH

Now consider what is true.

Element            Number of the left            Number on the right.

Ba                             1                                              1

O                              2                                             2

H                               4                                            4

Cl                              2                                             2

Nothing has changed going from the left to the right. You may wonder how you get 4 for the hydrogens.

Ba(OH)2  has 2 hydrogens. You multiply the 2 by the hydrogens in the brackets.

2HCl = The 2 in front affects both the hydrogens and the chlorines. There are 2 hydrogens from the HCl

Total: 2 + 2 = 4 hydrogens. The right side is done the same way.

You are not getting different results on the right side than those that you had on the left. Mass is preserved. 1 Ba + 2 Os + 4Hs and 2 Cls on the left, gives the same numbers on the right. There is no loss of mass.

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A nuclear reactor core must stay at or below 95 °C to remain in good working condition. Cool water at a temperature of 10 °C is
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Answer:

\large \boxed{\text{67 000 g}}

Explanation:

This is a problem in calorimetry — the measurement of the quantities of heat that flow from one object to another.

It is based on the Law of Conservation of Energy — Energy can be transformed from one type to another, but it cannot be destroyed or created.

If heat flows out of the reactor (negative), the same amount of heat must flow into the water (positive).

Since there is no change in total energy,

heat₁ + heat₂ = 0

The symbol for the quantity of heat transferred is q, so we can rewrite the word equation as

q₁ + q₂  = 0

The formula for the heat absorbed or released by an object is

 q = mCΔT, where

 m = the mass of the sample

  C = the specific heat capacity of the sample, and

ΔT = T_f - T_i = the change in temperature

1. Equation

There are two heat flows in this problem,

heat released by reactor + heat absorbed by water = 0

               q₁                  +                        q₂                     = 0

               q₁                  +                 m₂C₂ΔT₂                 = 0

2. Data:

q₁ = -23 746 kJ

m₂ = ?; C₂ = 4.184 J°C⁻¹g⁻¹;  T_f = 95 °C; T_i = 10 °C

3. Calculations

(a) Convert kilojoules to joules

q_{1} = -\text{23 746 kJ} \times \dfrac{\text{1000 J}}{\text{1 kJ}} = -\text{23 746 000 J}

(b) ΔT  

ΔT₂ = T_f - T_i = 95 °C - 10 °C = 85 °C

(c) m₂

\begin{array}{rcl}q_{1} + q_{2} & = & 0\\\text{-23 746 000 J} + m_{2} \times 4.184 \text{ J$^{\circ}$C$^{-1}$g$^{-1}$} \times 85 \, ^{\circ}\text{C} & = & 0\\\text{-23 746 000 J} + 356m_{2} \text{J$\cdot$g}^{-1} & = & 0\\356m_{2} \text{g}^{-1} & = & 23746000\\m_2&=& \dfrac{23746000}{\text{356 g}^{-1}}\\\\ & = & \textbf{67000 g}\\\end{array}\\

\text{You must circulate $\large \boxed{\textbf{67 000 g}}$ of water each hour.}

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