Answer:
there will be more miles of reactants
Answer:
The answer to your question is Na₂S, if you need to choices the other one is BaS
Explanation:
As a general rule, all the compounds that have sulfur, are insoluble in water, but the are some exceptions.
-Molecules with ammonia
-If the molecule has alkali metals is soluble
-If the molecule has Ca⁺², Sr⁺² and Ba⁺² is soluble in water.
From the compounds given, following the rules, the compound that is soluble in is Na₂S and perhaps BaS.
4) would be your correct answer
Answer:
0.504 M
Explanation:
Step 1: Write the balanced neutralization reaction
2 KOH + H₂SO₄ ⇒ K₂SO₄ + 2 H₂O
Step 2: Calculate the reacting moles of KOH
55.2 mL (0.0552 L) of 0.500 M KOH react. The reacting moles of KOH are:
0.0552 L × 0.500 mol/L = 0.0276 mol
Step 3: Calculate the moles of H₂SO₄ that reacted with 0.0276 moles of KOH
The molar ratio of KOH to H₂SO₄ is 2:1. The reacting moles of H₂SO₄ are 1/2 × 0.0276 mol = 0.0138 mol
Step 4: Calculate the concentration of H₂SO₄
0.0138 moles of H₂SO₄ are in 27.4 mL (0.0274 L). The molarity of H₂SO₄ is:
[H₂SO₄] = 0.0138 mol/0.0274 L = 0.504 M
