Answer:
They are counting in even numbers, so using my counting skills, the answer is 4.
This is asking you how far around that specific portion of the circle did the needle travel. I'm guessing you're in geometry and you're doing circle stuff right now. This is the arc length. The formula is
![l= \frac{central angle}{360} *2 \pi r](https://tex.z-dn.net/?f=l%3D%20%5Cfrac%7Bcentral%20angle%7D%7B360%7D%20%2A2%20%5Cpi%20r)
which is a combination of the circumference of a circle and its central angle. Our situation will look like this:
![l= \frac{100}{360} *2 \pi (20)](https://tex.z-dn.net/?f=l%3D%20%5Cfrac%7B100%7D%7B360%7D%20%2A2%20%5Cpi%20%2820%29)
If you leave your answer in terms of pi it would be
![11.1 \pi](https://tex.z-dn.net/?f=11.1%20%5Cpi%20)
or if you multiply it in, then your answer will be 34.9
For squrae
area=side²
perimiter=4(side)
for circle
area=pir²
circumference=2pir
side=diameter, diameter/2=radius=side/2
find area not covered
that is areasquare-areacircle
areasquare=26²=676 sqauare inches
areaciecle, diameter=side, 26/2=13, area=pi13²=169*3.14=530.66 square inches
areanotcovered=676-530.66=145.34 square inches not coverd
ratio of perimiter to circumferece
perimiter=4*26=104
circumference=2pir=2pi13=26pi=26*3.14=81.64
circumference to perimiter is 81.64/104=0.785
The coordinates of point B are (-4 , -2) ⇒ answer H
Step-by-step explanation:
In any circle
- The diameter of the circle passing through its center
- The center of the circle is the mid-point of all diameters
If (x , y) are the coordinates of the mid-point of a line whose end
points are
and
, then
and ![y=\frac{y_{1}+y_{2}}{2}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7By_%7B1%7D%2By_%7B2%7D%7D%7B2%7D)
∵ Point C is the center of a circle
∵ AB is the diameter of the circle
∴ C is the mid point of AB
∵ A = (2 , 6) ⇒ ![(x_{1},y_{1})](https://tex.z-dn.net/?f=%28x_%7B1%7D%2Cy_%7B1%7D%29)
∵ B = ![(x_{2},y_{2})](https://tex.z-dn.net/?f=%28x_%7B2%7D%2Cy_%7B2%7D%29)
∵ C = (-1 , 2) ⇒ (x , y)
- Use the rule of the mid-point above
∵ ![-1=\frac{2+x_{2}}{2}](https://tex.z-dn.net/?f=-1%3D%5Cfrac%7B2%2Bx_%7B2%7D%7D%7B2%7D)
- Multiply both sides by 2
∴ -2 = 2 + ![x_{2}](https://tex.z-dn.net/?f=x_%7B2%7D)
- Subtract 2 from both sides
∴
= -4
∴ The x-coordinate of point B is -4
∵ ![2=\frac{6+y_{2}}{2}](https://tex.z-dn.net/?f=2%3D%5Cfrac%7B6%2By_%7B2%7D%7D%7B2%7D)
- Multiply both sides by 2
∴ 4 = 6 + ![y_{2}](https://tex.z-dn.net/?f=y_%7B2%7D)
- Subtract 6 from both sides
∴
= -2
∴ The y-coordinate of point B is -2
The coordinates of point B are (-4 , -2)
Learn more:
You can learn more about the circle in brainly.com/question/9510228
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