1512 I believe! :) I would double all the dimensions first, then multiply them all together.
I am pretty sure the answer is 14
Answer:
1) k = 3
2) 3, 4, 5
3) k + (k + 2) + (k + 4) = 4k
4) 6, 8, 10
Step-by-step explanation:
Jared used the equation;
k + (k + 1) + (k + 2) = 4k
Let's find k.
3k + 3 = 4k
4k - 3k = 3
k = 3
Thus,the integers will be;
3, (3 + 1) and (3 + 2)
This is; 3, 4, 5
He is looking for consecutive even integers but yet got 3 and 5 which are odd numbers. However, he should have used the format;
k, (k + 2), (k + 4) as the 3 consecutive even integers.
Thus, rewriting the main equation gives;
k + k + 2 + k + 4 = 4k
3k + 6 = 4k
4k - 3k = 6
k = 6
Thus,the integers are;
6, (6 + 2), (6 + 4)
This is; 6, 8, 10
Solve the equation for x. X+48=649*(1/x)
None of the above. make sure you have it said the right way
