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4vir4ik [10]
3 years ago
15

W/18=3 I don't understand

Mathematics
2 answers:
Dmitrij [34]3 years ago
8 0
All you do is solve for W.
 you need to isolate the variable, and to do that you multiply by 18 on each side
 the /18 and the *18 will cancel each other out, leaving W by itself. Then 3*18 is equal to 54

W=54
Travka [436]3 years ago
6 0
If you want to solve for w:

w/18= 3
multiply both sides by 18

(w/18)(18)= (3)(18)
18 "cancels out" on the left side

w= 54


CHECK
54/18= 3
3= 3


ANSWER: w= 54

Hope this helps! :)
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4

Step-by-step explanation:

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6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B5x%2F8y%7D" id="TexFormula1" title="\sqrt[4]{5x/8y}" alt="\sqrt[4]{5x/8y}" al
Furkat [3]

Answer:  \frac{\sqrt[4]{10xy^3}}{2y}

where y is positive.

The 2y in the denominator is not inside the fourth root

==================================================

Work Shown:

\sqrt[4]{\frac{5x}{8y}}\\\\\\\sqrt[4]{\frac{5x*2y^3}{8y*2y^3}}\ \ \text{.... multiply top and bottom by } 2y^3\\\\\\\sqrt[4]{\frac{10xy^3}{16y^4}}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{16y^4}} \ \ \text{ ... break up the fourth root}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{(2y)^4}} \ \ \text{ ... rewrite } 16y^4 \text{ as } (2y)^4\\\\\\\frac{\sqrt[4]{10xy^3}}{2y} \ \ \text{... where y is positive}\\\\\\

The idea is to get something of the form a^4 in the denominator. In this case, a = 2y

To be able to reach the 16y^4, your teacher gave the hint to multiply top and bottom by 2y^3

For more examples, search out "rationalizing the denominator".

Keep in mind that \sqrt[4]{(2y)^4} = 2y only works if y isn't negative.

If y could be negative, then we'd have to say \sqrt[4]{(2y)^4} = |2y|. The absolute value bars ensure the result is never negative.

Furthermore, to avoid dividing by zero, we can't have y = 0. So all of this works as long as y > 0.

3 0
3 years ago
A teacher administers three different versions of a test to his students. The two-way table shows the results. Find each probabi
kakasveta [241]

The P(pass | Test A) is 31.81%, P(pass | Test B) is 29.87%, and P(pass | Test C) is 22.07%

<h3>What is probability?</h3>

It is defined as the ratio of the number of favourable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.

Part A:

Total number of students = 154

Total number of students passed the test = 49

The probability:

P(pass | Test A) = 49/154 = 31.81%

Part B:

Total number of students = 154

Total number of students passed the test = 46

The probability:

P(pass | Test B) = 46/154 = 29.87%

Similarly, for the probability:

P(pass | Test C) = 34/154 = 22.07%

Thus, the P(pass | Test A) is 31.81%, P(pass | Test B) is 29.87%, and P(pass | Test C) is 22.07%

Learn more about the probability here:

brainly.com/question/11234923

#SPJ1

5 0
2 years ago
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