A flower using 1 line segment and 8 rays

0.81 repeating decimal into a fraction

Daniel [21]

Answer:81/100

Step-by-step explanation:

0.81

0.0 tenths

0.00 hunderts

5 0

3 years ago

35. Explain the difference between the reciprocal of x^2

Scorpion4ik [409]

Answer:

As you can see, the difference between the reciprocal of $x^2$ and the inverse of $x^2$ is that $\frac{1}{x^2} =x^{-2}$ and $\sqrt{x} =x^{\frac{1}{2}$ .

Step-by-step explanation:

First lets find both the reciprocal of $x^2$ and the inverse of

Recall that the reciprocal of a value is where you take a fraction and swap the places of the terms. In the case of $x^2$ , 1 is the denominator, so

$\frac{x^2}{1} =\frac{1}{x^2}$

To find the inverse of a function, you first need swap the locations of x and y in the equation

$y=x^2\\\\x=y^2$

Now, you need to solve for y

$y^2=x\\\\y=\sqrt{x}$

Now, lets rewrite each of these to better compare them

$\frac{1}{x^2} =x^{-2}\\\\\sqrt{x} =x^{\frac{1}{2}$

As you can see, the difference between the reciprocal of $x^2$ and the inverse of

7 0

3 years ago

The endpoint of a line segment is (-9, 7). The midpoint of the segment is (10, -3). Find the other endpoint. *show work*

slavikrds [6]

First we will find the x coordinate.

x1+x2 / 2 = the x coordinate of the midpoint.

-9 + x2 / 2 = 10
x2/2 -4.5 = 10
x2/2 = 14.5
x2 = 29

Now the y coordinate:

y1+y2 /2 = y coordinate of the midpoint

7 + y2 / 2 = -3
y2/2 + 3.5 = -3
y2/2 = -6.5
y2 = -13

So the other endpoint is (29,-13)

I hope i am right :)

8 0

3 years ago

Factorize 2x²y⁴-6xy³

Gekata [30.6K]

Answer:

=2xy^3x(xy-3)

Step-by-step explanation:

2x^2y4-6xy^3

=2xy^3x(xy-3)

5 0

2 years ago

A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as

Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let X = number of seconds in the batch.

The probability of the random variable X is, p = 0.31.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...$

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

$P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888$

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

$=1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776$

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

$={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453$

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0

3 years ago