ANYONE??

Mathematics

1 answer:

RideAnS [48]3 years ago

5 0

Volume of a quadrangular pyramid=(1/3)bh
b=base
h=height

b=area of the base=area of a square=8.4 ft * 8.4 ft=70.56 ft²

Pythagoras theorem:
hypotenuse²=leg₁² + leg₂²

data:
hypotenuse=9.6 ft
leg₁=height=h
leg₂=8.4 ft /2=4.2 ft

(9.6 ft)²= h² + (4.2 ft)²
92.16 ft²=h²+17.64 ft²
h²=92.16 ft²-17.64 ft²
h²=74.52 ft²
h=√(74.52 ft²)=8.63 ft.

Volume of this quadrangular pyramid=(1/3)(70.56 ft²)(8.63 ft)=202.9 ft³≈202.3 ft³

Answer: ≈202.3 ft³

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