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bixtya [17]
2 years ago
7

Under his cell phone plan, Owen pays a flat cost of $46 per month and $3 per gigabyte, or part of a gigabyte. (For example, if h

e used 2.3 gigabytes, he would have to pay for 3 whole gigabytes.) He wants to keep his bill under $60 per month. What is the maximum whole number of gigabytes of data he can use while staying within his budget?
Mathematics
1 answer:
just olya [345]2 years ago
5 0

Answer:

4 gigs maybe

Step-by-step explanation:

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The slope of the line between two points is known as the rate of change in the relation.
borishaifa [10]
Slope=rise/run or changeiny/changeinx or (y2-y1)/(x2-x1) or (y1-y2)/(x1-x2)



so

pick any 2 points
(x,y)
(0,17) and (1,23)
slope=(y2-y1)/(x2-x1)
so
(23-17)/(1-0)=6/1=6
slope is 6
8 0
3 years ago
What is the answer to this math problem 40+40x0+1=
Anna71 [15]
PEMDAS is 
Parenthesis
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therefore, you would do 40*0=0+40+1=41 
5 0
3 years ago
Please help me y'all this is due soon. :))​
Rashid [163]
Not sure for the others but a is 55 cause ps is half a circle witch is 180 and pt is 125 so just subtract 180 - 125 =55
6 0
2 years ago
The concentration of dichlorodiphenyltrichloroethane (DDT - an infamous pesticide) in Lake Michigan has been declining exponenti
mojhsa [17]

Answer: A) y=13e^{-0.1359t}

              B) H = 5.10

              C) Yes

Step-by-step explanation: <u>Exponential</u> <u>Decay</u> <u>function</u> is a model that describes the reducing of an amount by a constant rate over time. Generally, it is written in the form: y(t)=Ce^{rt}

A) C is initial quantity, in this case, the initial concentration of DDT. To determine r, using the data given:

y(t)=Ce^{rt}

2.22=13e^{13r}

e^{13r}=0.1708

Using a natural logarithm property called <em>power rule:</em>

13r=ln(0.1708)

r=\frac{ln(0.1708)}{13}

r=-0.1359

The decay function for concentration of DDT through the years is y(t)=13e^{-0.1359t}

B) The value of H is calculated by y=C(0.5)^{\frac{t}{H} }

2.22=13(0.5)^{\frac{13}{H} }

(0.5)^{\frac{13}{H} }=0.1708

Again, using power rule for logarithm:

\frac{13}{H} log(0.5)=log(0.1708)

\frac{13}{H} =\frac{log(0.1708)}{log(0.5)}

\frac{13}{H} =2.55

H = 5.10

Constant H in the half-life formula is H=5.10

C) Using model y(t)=13e^{-0.1359t} to determine concentration of DDT in 1995:

y(24)=13e^{-0.1359.24}

y(24) = 0.5

By 1995, the concentration of DDT is 0.5 ppm, so using this model is possible to reduce such amount and more of DDT.

8 0
2 years ago
Show the work pleasee
Nataly [62]

Answer:

a

Step-by-step explanation:

6 0
2 years ago
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