Answer:
g(0.9) ≈ -2.6
g(1.1) ≈ 0.6
For 1.1 the estimation is a bit too high and for 0.9 it is too low.
Step-by-step explanation:
For values of x near 1 we can estimate g(x) with t(x) = g'(1) (x-1) + g(1). Note that g'(1) = 1²+15 = 16, and for values near one g'(x) is increasing because x² is increasing for positive values. This means that the tangent line t(x) will be above the graph of g, and the estimates we will make are a bit too big for values at the right of 1, like 1.1, and they will be too low for values at the left like 0.9.
For 0.9, we estimate
g(0.9) ≈ 16* (-0.1) -1 = -2.6
g(1.1) ≈ 16* 0.1 -1 = 0.6
Answer:
The answer is option 1.
Step-by-step explanation:
In order to simplify the expressions, you have to collect like terms :
3a² + 9ab + 5 - 4a² - 4ab + 3
= (3a² - 4a²) + (9ab - 4ab) + (5 + 3)
= -a² + 5ab + 8
The equation that models the difference in the projected enrollments for
public schools and private schools as a function of the number of years
since 1985 is B - R = (-18.53t^2 + 975.8t + 48140) - (80.8t + 8049) = -18.53t^2 + 975.8t + 48140 - 80.8t - 8049 = -18.53t^2 + 895t + 40091
E^-0.3 = 0.74 from the calculator
Answer:
As per the statement: Hannah already had 44 photos on her camera when she arrived in Rome.Then she took 24 photos each day for 6 days.
Let x represented day and y represents the number of photo
Total number of 24 photo in x days is, 24x
then; as per the given statement our equation becomes;
y = 24x+44 .....[1]
now, to find the total number of photos took by Hannah for 6 days in Rome;
put x = 6 in [1] we get;
y = 24(6) + 44 = 188
Therefore, the total number of photos on Hannah's Camera is, 188 photos.
To, find the initial value for the linear function y =24x +44.
Initial value or y-intercept, is the output value when the input of a linear function is zero i.e, x = 0.
Substitute x =0 in y =24x +44
y= 24(0) + 44
y = 0 + 44
y = 44
Therefore, the initial value for the equation y =24x+44 is 44 photos.
