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2 years ago

7

Find the distance between the two numbers on a number line. Write your answer as a mixed number.

1 answer:

yulyashka [42]2 years ago

7 0

Answer:

316

Step-by-step explanation:

(-323) - (-7) = 316

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Write an inequality pls help me on this question!

Helen [10]

Answer:

y = -2x + -3

Step-by-step explanation:

The line has a slope of -2 because when counting from point to point, its 2 down and one over; 2/1 or 2 (negative because the line is going down)

The intercept in -3 because thats the first place the line touches the y axis.

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2 years ago

I need a little bit of help here ☹️

Grace [21]

-3(y+2)^2 - 5 + 6y
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Answer
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3 years ago

How do find the height of the parallelogram?

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3 years ago

Find a counterexample to show that the conjecture is false. Any number that is divisible by 2 is also divisible by 6.

Anon25 [30]

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2 years ago

Read 2 more answers

An arched drainage culvert can be modelled by the function:

Zanzabum

Substitute 136.5 for y.

$136.5=\frac{x(191-x)}{60}$

$8190=x(191-x)$

$8190=191x-x^{2}$

$x^{2} -191x+8190=0$

Compare this equation with $ax^{2} +bx+c=0$

a = 1, b = - 191, c = 8190

$x=\frac{-b+\sqrt{b^{2}-4ac } }{2}$ or

$x=\frac{-b-\sqrt{b^{2}-4ac } }{2}$

$x=\frac{191+\sqrt{191^{2}-4(1)(8190) } }{2}$ or

$x=\frac{191-\sqrt{191^{2}-4(1)(8190) } }{2}$

$x=\frac{191+\sqrt{36481-32760 } }{2}$ or

$x=\frac{191-\sqrt{36481-32760 } }{2}$

$x=\frac{191+\sqrt{3721 } }{2}$ or

$x=\frac{191-\sqrt{3721 } }{2}$

$x=\frac{191+61}{2}$ or

$x=\frac{191-61}{2}$

$x=\frac{252}{2}$ or

$x=\frac{130}{2}$

x = 126 or x = 65

Hence, the points on the curve are (65, 136.5) and (126, 136.5).

The width of the air space is the distance between these points.

Width = $\sqrt{(x_{2}- x_{1})^{2} +( y_{2}- y_{1}) ^{2}$

= $\sqrt{(126- 65)^{2} +(136.5-136.5) ^{2}$

= 126 - 65

= 61

Hence, width of the air space is 61m.

5 0

2 years ago