Solve for c. a(b-c)=d
2 answers:
<u>D. </u><u><em>c=ab-d/a is the correct answer.</em></u> First you had to add by -ab from both sides of equation, and it gave us, , or
. Then divide by -a from both sides of equation, and it gave us,
, and it gave us the answer is<u><em> </em></u><u><em>c=ab-d/a is the right answer.</em></u> Hope this helps! And thank you for posting your question at here on brainly, and have a great day. -Charlie
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Given:
The given quadratic polynomial is :
To find:
The quadratic polynomial whose zeroes are negatives of the zeroes of the given polynomial.
Solution:
We have,
Equate the polynomial with 0 to find the zeroes.
Splitting the middle term, we get
The zeroes of the given polynomial are -3 and 4.
The zeroes of a quadratic polynomial are negatives of the zeroes of the given polynomial. So, the zeroes of the required polynomial are 3 and -4.
A quadratic polynomial is defined as:
Therefore, the required polynomial is .