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Svetlanka [38]
3 years ago
6

Complete the statement by typing the letter of the angle. m∠ =54º

Mathematics
2 answers:
satela [25.4K]3 years ago
5 0

Answer:

B is the answer.

Step-by-step explanation:

Got it right on Ed.

tekilochka [14]3 years ago
3 0

Answer:

x = 16

∠A = 39

∠B = 54

∠C = 87

Step-by-step explanation:

Make a equation of all of the angles added together is equal to 180 since the angles of a triangle added together is 180

(4x-10)+(2x+7)+(7x-25)=180

combine like terms

4x+2x+7x-10+7-25 = 180

13x-28=180

solve for x

13x=208

x = 16

plug in x to find the measure of the angle

∠A = 2(16) + 7 = 39

∠B = 4(16) - 10 = 54

∠C = 7(16) - 25 = 87

Add them together to double check your answer

39 + 54 + 87 = 180

hope this helps

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If T: (x, y) → (x + 6, y + 4), then T-1: (x,y) → _____.
alexgriva [62]

T is a linear transformation from R²→R² with basis {(1,0),(0,1)}
T: (x,y)→(x+6,y+4)

A function from one vector space to another that preserves the underlying (linear) structure of each vector space is called a linear transformation.

Then the vector (1,0) goes to (1+6,4)=(7,4)=7(1,0)+4(0,1)

and the vector (0,1) goes to (6,1+4)=(6,5)=6(1,0)+5(0,1)

So, the matrix of the transformation is

\left[\begin{array}{ccc}7&6\\4&5\end{array}\right]

The inverse of the matrix is

\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]

So, the Inverse Transformation is given by

T^{-1}(x,y)=\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =(\frac{5x-6y}{11}, \frac{-4x+7y}{11})

So, no option is correct. And the answer is

T^{-1}(x,y)=(\frac{5x-6y}{11}, \frac{-4x+7y}{11})

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brainly.com/question/13005179

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5 0
2 years ago
If it takes 6 hours for a plane to travel 720km with a tail wind and 8 hours to make the return trip with a head wind. Find the
denis-greek [22]

The speed of wind and plane are 105 kmph and 15 kmph respectively.

<u>Solution:</u>

Given, it takes 6 hours for a plane to travel 720 km with a tail wind and 8 hours to make the return trip with a head wind.  

We have to find the air speed of the plane and speed of the wind.

Now, let the speed wind be "a" and speed of aeroplane be "b"

And, we know that, distance = speed x time.

\text { Now, at tail wind } \rightarrow 720=(a+b) \times 6 \rightarrow a+b=\frac{720}{6} \rightarrow a+b=120 \rightarrow(1)

Now at head wind → 720=(a-b) \times 8 \rightarrow a-b=\frac{720}{8} \rightarrow a-b=90 \rightarrow(2)

So, solve (1) and (2) by addition

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substitute a value in (1) ⇒ 105 + b = 120

⇒ b = 120 – 105 ⇒ b = 15.

Here, relative speed of plane during tail wind is 120 kmph and during head wind is 90 kmph.

Hence, speed of wind and plane are 105 kmph and 15 kmph respectively.

6 0
3 years ago
A store is having a sale on chocolate chips and walnuts. For 3 pounds of chocolate chips and 5 pounds of walnuts, the total cost
mrs_skeptik [129]

Answer:

Step-by-step explanation:

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5 0
3 years ago
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fiasKO [112]
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4 0
3 years ago
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Stels [109]

Answer:

hi

Step-by-step explanation:

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i think so…

8 0
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