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3 years ago

6 students are working on math 2/3 of them are working on fractions. How many of them are working on fractions

Mathematics

1 answer:

TiliK225 [7]3 years ago

3 0

4 students are working on fractions

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A circle is centered at Q(1,-5) and has a radius of 5. Where does the point Y(4,-1) lie?

marta [7]

Answer:

Point Y (4, -1) lies on the circle.

Step-by-step explanation:

Distance = √[(x2-x1)² + (y2 - y1)²] = √[(4-1)² + (-1-(-5))²] = √[3² + 4²]= √25 = 5

Point Y (4, -1) lies on the circle, because the distance from the center to this point equals radius of the circle.

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3 years ago

Find the average value of the function on the given interval.<br> f(x)=2 ln x; [1,e]

JulijaS [17]

Answer:

$f_{avg}=\frac{1}{e-1}$

Step-by-step explanation:

We are given that a function

$f(x)=2lnx$

We have to find the average value of function on the given interval [1,e]

Average value of function on interval [a,b] is given by

$\frac{1}{b-a}\int_{a}^{b}f(x)dx$

Using the formula

$f_{avg}=\frac{1}{e-1}\int_{1}^{e}lnx dx$

By Parts integration formula

$\int(uv)dx=u\int vdx-\int(\frac{du}{dx}\int vdx)dx$

u=ln x and v=dx

Apply by parts integration

$f_{avg}=\frac{1}{e-1}([xlnx]^{e}_{1}-\int_{1}^{e}(\frac{1}{x}\times xdx))$

$f_{avg}=\frac{1}{e-1}(elne-ln1-[x]^{e}_{1})$

$f_{avg}=\frac{1}{e-1}(e-0-e+1)=\frac{1}{e-1}$

By using property lne=1,ln 1=0

$f_{avg}=\frac{1}{e-1}$

8 0

3 years ago

Mrs. Hargrove owes the doctor $34.56. she gives the clerk $50.00 What is the total amount of change Mrs.Hargrove should receive

Valentin [98]

Answer:

$15.44

Step-by-step explanation:

50 - 34.56 = 15.44

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2 years ago

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Find the perimeter and area of each figure.

ASHA 777 [7]

Answer:

Perimeter = 89mm

area= 528 or 220

Step-by-step explanation:

hope this is useful

3 0

4 years ago

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The assembly time for a product is uniformly distributed between 6 to 10 minutes. the expected assembly time (in minutes) is

Marta_Voda [28]

The expected assembly time is the middle of the range of the uniform distribution, 8 minutes.

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4 years ago