1 - 9
2 - 87
3 - -2
4 - -9
that’s the answers for them :), have a great day !! :)
Answer: possible values of Range will be values that are >=91 or <=998
Step-by-step explanation:
Given that :
Set Q contains 20 positive integer values. The smallest value in Set Q is a single digit value and the largest value in Set Q is a three digit value.
Therefore,
given that the smallest value in set Q is a one digit number :
Then lower unit = 1, upper unit = 9( this represents the lowest and highest one digit number)
Also, the largest value in Set Q is a three digit value:
Then lower unit = 100, upper unit = 999 ( this represents the lowest and highest 3 digit numbers).
Therefore, the possible values of the range in SET Q:
The maximum possible range of the values in set Q = (Highest possible three digit value - lowest possible one digit) = (999 - 1) = 998
The least possible range of values in set Q = (lowest possible three digit value - highest possible one digit value) = (100 - 9) = 91
Answer: x-5
Step-by-step explanation: well idk
Answer:
y =2
Step-by-step explanation:
Substitute -10 for x:
2(-10)-9y = -38
-20-9y = -38
-9y = -18
9y = 18
y = 2
If you do 81 x 9 which equals 729. If you want to check, you do 729 divided by 9 and you get 81.
