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Anarel [89]
3 years ago
15

Write the equation in vertex form of the parabola with the vertex (-4,-4) that goes through the point (-2,-16)

Mathematics
1 answer:
Brrunno [24]3 years ago
5 0

Answer:

- 3(x + 4) {}^{2}  - 4

Step-by-step explanation:

Vertex form is

a(x - h) {}^{2}  + k = f(x)

We know that h and k are both -4. Let x be -2 and y be -16.

a( - 2  + 4) {}^{2}   - 4 =  - 16

a(2) {}^{2}  - 4 =  - 16

4a - 4 =  - 16

4a =  - 12

a =  - 3

So the equation in vertex form is

- 3(x  + 4) {}^{2}  - 4

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VLD [36.1K]
1. 3x - 2y = 0 => y = 3/2x
4x + 2y = 14<=> 4x + 2*(3/2x) = 14<=> 7x = 14<=> x = 2 & y = 3
2.3p + q = 7=> q = 7 - 3p
2p - 2q = -6<=> 2p - 2*(7-3p) = -6<=> 2p - 14 + 6p = -6<=> 8p = -6 + 14 = 8<=> p = 1 & q = 4
3.3x - 2y = 1=> x = (1+2y)/3
8x + 3y = 2<=> 8*(1+2y)/3 + 3y = 2<=> 8*(1+2y)/3 - 2 = -3y<=> 3*(8*(1+2y)/3 - 2) = -3*(3y)<=> 8*(1+2y) - 6 = -9y<=> 8 + 16y - 6 = -9y<=> 2 = -25y<=> y = -2/25 & x = 7/25
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3 years ago
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Lyrx [107]

Answer:

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Step-by-step explanation:

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3 years ago
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Kruka [31]

Answer:

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Step-by-step explanation:

To evaluate this, start by turning each into improper fractions.

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vekshin1
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Read 2 more answers
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